Question

Ibuprofen, a headache remedy, contains 75.69% C, 8.80% H, and 15.51% O by mass and has a molar mass of 206 g/mol. Express your answers as chemical formulas separated by a comma. nothing Request Answer Part B Cadaverine, a foul-smelling substance produced by the action of bacteria on meat, contains 58.55% C, 13.81% H, and 27.40% N by mass; its molar mass is 102.2 g/mol. Express your answers as chemical formulas separated by a comma. nothing Request Answer Part C Epinephrine (adrenaline), a hormone secreted into the bloodstream in times of danger or stress, contains 59.0% C, 7.1% H, 26.2% O, and 7.7% N by mass; its molar mass is about 180 amu. Express your answers as chemical formulas separated by a comma. nothing

Answer 1

Answer:

A)Molecular formula of ibuprofen is$C_{13}H_{18}O_2$

B)Molecular formula of Cadaverine is $C_{5}H_{14}N_2$

C)Molecular formula of Epinephrine is $C_9H_{13}O_3N_1$

Explanation:

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100$

A) Ibuprofen, a headache remedy, contains 75.69% C, 8.80% H, and 15.51% O by mass.

Molar mass of ibuprofen = 206 g/mol.

Let the molecular formula of ibuprofen be =$C_xH_yO_z$

Number of carbon atoms in 1 molecule of ibuprofen ;

$75.69\%=\frac{x\times 12 g/mol}{206 g/mol}\times 100$

$x=\frac{75.69\times 206 g/mol}{100\times 12 g/mol}=12.99\approx 13$

Number of hydrogen atoms in 1 molecule of ibuprofen ;

$8.80\%=\frac{y\times 1 g/mol}{206 g/mol}\times 100$

$y=\frac{8.80\times 206 g/mol}{100\times 1 g/mol}=18.12\approx 18$

Number of oxygen atoms in 1 molecule of ibuprofen ;

$15.51\%=\frac{z\times 16 g/mol}{206 g/mol}\times 100$

$z=\frac{15.51\times 206 g/mol}{100\times 16 g/mol}=1.99\approx 2$

Molecular formula of ibuprofen :

= $C_xH_yO_z= C_{13}H_{18}O_2$

B)  Cadaverine contains 58.55% C, 13.81% H, and 27.40% N by mass

Molar mass of Cadaverine = 102.2 g/mol.

Let the molecular formula of Cadaverine be =$C_xH_yN_z$

Number of carbon atoms in 1 molecule of Cadaverine ;

$58.55\%=\frac{x\times 12 g/mol}{102.2 g/mol}\times 100$

$x=\frac{58.55\times 102.2 g/mol}{100\times 12 g/mol}=4.98\approx 5$

Number of hydrogen atoms in 1 molecule of Cadaverine ;

$13.81\%=\frac{y\times 1 g/mol}{102.2 g/mol}\times 100$

$y=\frac{13.81\times 102.2 g/mol}{100\times 1 g/mol}=14.11\approx 14$

Number of nitrogen atoms in 1 molecule of Cadaverine ;

$27.40\%=\frac{z\times 14 g/mol}{102.2 g/mol}\times 100$

$z=\frac{27.40\times 102.2 g/mol}{100\times 14 g/mol}=2.00\approx 2$

Molecular formula of Cadaverine :

= $C_xH_yN_z= C_{5}H_{14}N_2$

C) Epinephrine  contains 59.0% C, 7.1% H, 26.2% O, and 7.7% N by mass

Molar mass of Epinephrine  = 180 g/mol.

Let the molecular formula of Epinephrine  be =$C_xH_yO_zN_w$

Number of carbon atoms in 1 molecule of Epinephrine  ;

$59.0\%=\frac{x\times 12 g/mol}{180 g/mol}\times 100$

$x=\frac{59.0\times 180 g/mol}{100\times 12 g/mol}=8.85\approx 9$

Number of hydrogen atoms in 1 molecule of Epinephrine  ;

$7.1\%=\frac{y\times 1 g/mol}{180 g/mol}\times 100$

$y=\frac{7.1\times 180 g/mol}{100\times 1 g/mol}=12.78\approx 13$

Number of oxygen atoms in 1 molecule of Epinephrine  ;

$26.2\%=\frac{z\times 16 g/mol}{180 g/mol}\times 100$

$z=\frac{26.2\times 180 g/mol}{100\times 16 g/mol}=2.94\approx 3$

Number of nitrogen atoms in 1 molecule of Epinephrine  ;

$7.7\%=\frac{w\times 14 g/mol}{180 g/mol}\times 100$

$w=\frac{7.7\times 180 g/mol}{100\times 14 g/mol}=0.99\approx 1$

Molecular formula of Epinephrine  :

= $C_xH_yO_zN_w= C_9H_{13}O_3N_1$