PART I
Angular size of the minor arc .
Half of the chord an the radius makes a right angled triangle with the radius as the hypotenuse and half of the chord as one of the shorter side.
Therefore, using trigonometric ratio, sine = opp/hyp
sine θ = 8/10 where θ is half the minor angle
θ = 53.13
Therefore, the angular size of the minor arc will be 53.13 × 2 = 106.26°
PART II
The length of an arc is given by (θ/360 )× 2πr
where θ is the angle subtended by the arc to the center of the circle and r is the radius of the circle.
Therefore, length = (106.26/360) × 3.142 × 2×10
= 18.548 Inches
Answer:
D) n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3
Step-by-step explanation:
The given polynomial is 8mn^5 -2m^6 +5m^2 n^4 - m^3 n^3 + n^6 - 4m^6 + 9m^2n^4 -mn^5 - 4m^3n^3
Now we have to identify the like terms and simplify.
Like terms are nothing but the terms which have the same variables with same powers.
= (8mn^5 - mn^5) -2m^6 - 4m^6 + 5m^2 n^4 + 9m^2 n^4 - m^3n^3 - 4m^3n^3 +n^6
Now combine the like terms
= 7mn^5 - 6m^6 +14m^2 n^4-5m^3n^3 + n^6
It can be written in standard form
= n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3
The answer is D)
Hope this will helpful.
Thank you.
Let the number of pages read on day 1 be = x
Then on day 2 he read twice the pages from day one, it is = 2x
On 3rd day he read 6 pages less than 1st day, it is = x-6
Total pages are = 458
The equation becomes: 



So on the third day, Aiden read
pages.
Answer: The answer is A 17in2
Step-by-step explanation:
In the question it states that the triangles are congruent (both the same).
first I found the area of the top orange triangle.
the formula to find the area of a triangle is
(base times Height).
so I did
which gave me 8.27.
Since the triangles are congruent (the same) they would both have the same area along with base and height. so I multiplied 8.27 by 2 (because there are two triangles) and got 16.54 which rounds up to 17.
the question also stated to find the APPROXIMATE area (close to the actual, but not completely accurate or exact.)