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sveta [45]
2 years ago
9

A sea turtle is 3 feet below the surface of the sea. If its position can be recorded as −3 feet, what would the position 0 repre

sent in this situation?
Mathematics
2 answers:
lord [1]2 years ago
8 0

Answer:

The answer is sea level

Step-by-step explanation:

Sphinxa [80]2 years ago
7 0
The answer is 3 because 3+0 is equal to 3
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XY=7a,YZ=5a,XZ=6a+24
leonid [27]
7a + 5a = 6a + 24 
<span>6a = 24 </span>
<span>a = 4 </span>
<span>XZ = 6(4) + 24 </span>
<span>XZ = 48 </span>
5 0
2 years ago
Jana is ordering a list of numbers from least to greatest. StartRoot 7 squared EndRoot, StartRoot 7 EndRoot, Four-fifths, StartR
makvit [3.9K]

Answer:

The answer is D

Step-by-step explanation:

\frac{4}{5} = 0.8

\sqrt{7} = 2.64

2.64 > 0.8 because 2 is a whole number while 0.8 is a decimal

8 0
2 years ago
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Cameras are set up to watch an intersection and determine how many cars are let through with each green light interval. This stu
sergij07 [2.7K]

Answer Choices:

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Answer:

Observational

3 0
2 years ago
An astronaut on the moon throws a baseball upward. the astronaut is 6​ ft, 6 in.​ tall, and the initial velocity of the ball is
marta [7]

Answer:

Step-by-step explanation:

The position function is

s(t)=-2.7t^2+50t+6.5 and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:

10=-2.7t^2+50t+6.5 and

0=-2.7t^2+50t-3.5 and factor that however you are currently factoring quadratics in class to get

t = .07 sec and t = 18.45 sec

There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).

For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:

0=-2.7t^2+50t+6.5 and factor that to get

t = -.129 sec and t = 18.65 sec

Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.

4 0
1 year ago
Mr Hughes is competing in the Mr. Legs campaign to raise money for the coral shores high school scholarship fund. On the first d
lakkis [162]
<span>The number of dollars collected can be modelled by both a linear model and an exponential model. To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8) The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3 y - 2 = 3(x - 1) = 3x - 3 y = 3x - 3 + 2 = 3x - 1 Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17 To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2. 8 = 2r^(3 - 1) = 2r^2 r^2 = 8/2 = 4 r = sqrt(4) = 2 Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>
4 0
2 years ago
Read 2 more answers
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