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Aneli [31]
2 years ago
3

A beauty pageant is being held with thirty contestants. Nancy and her 4 friends are all competing. The top 5 contestants go to s

tate finals. What are the chances that Nancy, Lisa, Phyllis, Jackie, and Erin are selected to go to the state finals in that order?
Mathematics
1 answer:
gavmur [86]2 years ago
8 0

Answer:

1/17100720

Step-by-step explanation:

P=25!30!

=25!/30⋅29⋅28⋅27⋅26⋅25!

=1/30⋅29⋅28⋅27⋅26

=1/117100720

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xz_007 [3.2K]
Well...
$6.50/64= about $0.10
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(/ means per)

7 0
2 years ago
What is the multiplicative rate of change for the exponential function f(x) = f start bracket x end bracket equals two start bra
zvonat [6]

Answer:

0.4

Step-by-step explanation:

got it right on quiz

5 0
2 years ago
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A parabolic satellite dish reflects signals to the dish’s focal point. An antenna designer analyzed signals transmitted to a sat
ivolga24 [154]

Answer:

c=\frac{16}{39}

Step-by-step explanation:

The probability density function is :

f(x)=c(1-\frac{1}{16}x^{2})

With 0 < x < 3

To be a valid probability density function :

\int\limits^b_a {f(x)} \,dx=1

Where a < x < b

And also

f(x) ≥ 0 for a < x < b

Applying this to the probability density function of the exercise :

\int\limits^3_0 {c(1-\frac{1}{16}x^{2})} \, dx=1

c\int\limits^3_0 {(1-\frac{1}{16}x^{2})} \, dx=1

c(3-\frac{1}{16}\frac{3^{3}}{3})=1

c(\frac{39}{16})=1

c=\frac{16}{39}

We can verify by replacing ''c'' in the original probability density function and integrating :

\int\limits^3_0 {\frac{16}{39}(1-\frac{1}{16}x^{2})} \, dx=

=\frac{16}{39}.(3)-\frac{1}{39}.(\frac{3^{3}}{3})=\frac{16}{13}-\frac{3}{13}=\frac{13}{13}=1

Also, f(x) ≥ 0 for 0 < x < 3

4 0
3 years ago
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Answer:

22,891.20

Step-by-step explanation:

I took this quiz and got it right.

6 0
2 years ago
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Which ordered pair is a solution of the equation?
noname [10]

Answer:

neither.

Step-by-step explanation:

7 0
2 years ago
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