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vodka [1.7K]
1 year ago
5

For x, y ∈ R, prove that ||x| − |y|| ≤ |x − y|, (Hint: consider x = y + (x − y)).​

Mathematics
1 answer:
dlinn [17]1 year ago
7 0

Using the triangular inequality (and the given hint!), we have

|x|=|(x-y)+y|\leq|x-y|+|y|\implies|x|-|y|\leq|x-y|

Similarly,

|y|=|(y-x)+x|\leq|x-y|+|x|\implies|y|-|x|\leq|x-y|\implies -|x-y| \leq |x|-|y|

We managed to bound the quantities in this fashion:

-b\leq a\leq b \implies |a|

And thus we have

||x|-|y||\leq |x-y|

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A motorcycle has an initial speed of u m/s. It accelerates to a speed of 1.2u in 10 seconds. The motorcycle then travels at a co
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Find the inverse of y=x2-10x
anzhelika [568]
<span>this is pretty hard but here is your answer 
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y = x^2 - 10x + 25 - 25

<span> y = (x-5)^2 - 25 </span>

<span> y+25 = (x-5)^2 </span>

<span> x-5 = +/-sqrt(y+25) </span>

 

<span> And you get TWO inverses: </span>

 

<span> x = 5 + sqrt(y+25), for x>=5 </span>

<span> x = 5 - sqrt(y+25), for x<=5</span>


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