Answer:
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Explanation:
Example of an irreverseble isothermal process is mixing of two fluids on the same temperature - it requires a lot of energy to unmix Jack and coke. ... Example of an reversible process with changing temperature is isentropic expansion.
Answer:
The long derivation for work of a mechanically reversible, isothermal compression was done with detailed steps as shown in the attachment.
Explanation:
what is applied here is a long derivation from Work done in an isobaric process, the expression for the compressibility factor (Z) and the equation of state that was given. The requisite knowledge of Differentiation and Integration was used.
The detailed derivation from firs principle is as shown in the attachment.
Answer:

Explanation:
Reynolds number:
Reynolds number describe the type of flow.If Reynolds number is too high then flow is called turbulent flow and Reynolds is low then flow is called laminar flow .
Reynolds number is a dimensionless number.Reynolds number given is the ratio of inertia force to the viscous force.

For plate can be given as

Where ρ is the density of fluid , v is the average velocity of fluid and μ is the dynamic viscosity of fluid.
Flow on plate is a external flow .The values of Reynolds number for different flow given as


Answer:
For aluminum 110.53 C
For copper 110.32 C
Explanation:
Heat transmission through a plate (considering it as an infinite plate, as in omitting the effects at the borders) follows this equation:

Where
q: heat transferred
k: conduction coeficient
A: surface area
th: hot temperature
tc: cold temperature
d: thickness of the plate
Rearranging the terms:
d * q = k * A * (th - tc)


The surface area is:


If the pan is aluminum:

If the pan is copper:

Answer:
Total no. of ways to line up cars is 20! = 2.43 c 10^18
Probability that the cars alternate is 0.00001 or 0.001%
Explanation:
Since, the position of a car is random.Therefore, number ways in which cars can line up is given as:
<u>No. of ways = 20! = 2.43 x 10^18</u>
For the probability that cars alternate, two groups will be formed, one consisting of US-made 10 cars and other containing 10 foreign made. The number of favorable outcomes for this can be found out as the arrangements of 2! between these groups multiplied by the arrangements of 10! for each group, due to the arrangements among the groups themselves.
Favorable Outcomes = 2! x 10! x 10!
Thus the probability of event will be:
Probability = Favorable Outcomes/Total No. of Ways
Probability = (2! x 10! x 10!)/20!
<u>Probability = 0.00001 = 0.001%</u>