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Lelu [443]
2 years ago
7

What is a standard procedure for dividing by a two-digit divisor.?

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
4 0
In a standard equation of dividing a two digit divisor one must follow these steps:

1. Double check if the first two digits of the dividend are equal or larger that the divisor. Start dividing if so. 

2. Write the answer above the second digit (or third if the first two digits' value is smaller than the divisor).

3. Multiply the answer with the divisor and subtract it from the dividend (digits used).

4. From the answer to the subtraction, add the next digit to the right of the dividend and repeat process until you get the total quotient.

5. In cases of remainders (extra numbers not divisible by the divisor), write them to the right of the quotient.

Please see attached picture for reference.

Hope this helps.

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Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b
horrorfan [7]

Answer:

a. X\sim N(\mu = 6.1, \sigma = 1.9) b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is z_{1} = (6.4-6.1)/1.9 = 0.1579 and the z-score related to 7 kg is z_{2} = (7-6.1)/1.9 = 0.4737, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0
2 years ago
A grocery sold 5kg of wheat flour at Rs30 per kg and gained 20%. If he had sold it at Rs27 per kg, what would be his gain or los
maria [59]

Answer:

His gain percent would have been 8%

Step-by-step explanation:

The key to answering this question is to first calculate the price at which the wheat flour was bought.

Mathematically;

% profit = (selling price-cost price)/cost price * 100%

Let the cost price be $x

Thus;

% profit = (30-x)/x * 100

20 = 100(30-x)/x

20x = 3000-100x

100x + 20x = 3000

120x = 3000

x = 3000/120

x = Rs 25

So let’s assume he sold at Rs 27

His profit would have been 27-25 = 2

His gain or loss percentage would’ve been;

2/25 * 100/1 = 200/25 = 8% (gain, since selling price is greater than the cost price)

3 0
2 years ago
the population of Ketcham high school has been decreasing by 5 % per year.if it's population is currently 2600 which of the foll
kap26 [50]
5% = .05
2600 x .05 = 130
130 x 2 = 260
2600 - 260 = 2340

The population will be 2340 people.
6 0
2 years ago
"Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per min
Lapatulllka [165]
First we need to find Mia's speed (v) in km/min

v = distance travelled/ time 
v = 3 km/20 minutes
v = 0.15 km /min

in order to convert the speed into mile/min, we need to use the conversion factor given in which for every kilometer, there is 0.6 miles. 

v = 0.15 km/min *(0.6 miles/ km) 
v =0.09 miles/min

therefore the speed in miles/min is 0.09 miles/min
4 0
2 years ago
Read 2 more answers
at the end of the day vegetables at farm market sell for $2.00 a pound and a bakery costs $3.50. if Charlene wants to buy a bask
9966 [12]
10=2x+3,50 |-3,50
6,50=2x |:2
3,25=x

10=2x+7 |-7
3=2x |:2
1,5=x

You didnt say how many bakery she wants to buy, so i did one inequality for 1 bakery anderen for the maximum of 2.
8 0
2 years ago
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