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olga_2 [115]
2 years ago
14

1. Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 50 L against a constant external pressure

of 1.5 atm. (1 L • atm = 101 J)
2. Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 50 L against a constant external pressure of 1.5 atm. (1 L • atm = 101 J +5.3 kJ -7.6 kJ +7.5 kJ -5.3 kJ)
Chemistry
1 answer:
Ira Lisetskai [31]2 years ago
5 0

Answer:

w = -3.8KJ

Explanation:

The work done on a system which is under an external pressure

P = w = - \int\limits^._. {p} \, dV \\w = - PΔV\\\\

P = 1.5 atm

ΔV = 40  − 15 = 25 L

w = - P ΔV = -1.5 (25) = - 37.5 L.atm

w = 37.5 X 101.325  J ≈ − 3800 J = −3.8 KJ

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8 0
2 years ago
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A 100-W lightbulb is placed in a cylinder equipped with a moveable piston. The lightbulb is turned on for 0.020 h, and the assem
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Answer: The workdone W = 505J

Explanation:

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W= - PΔV

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2 years ago
The standard free energy ( Δ G ∘ ′ ) (ΔG∘′) of the creatine kinase reaction is − 12.6 kJ ⋅ mol − 1 . −12.6 kJ⋅mol−1. The Δ G ΔG
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Answer:

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Explanation:

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ΔG = -0.1 KJ/mole  =  -100 J/mole

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But,

Qc    = [Creatine phosphate]*[ADP]/[creatine]*[ATP]

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          = 2.1896 *10^-5 M

          = 21.896*10^-6 μM

Therefore, the concentration of [ADP] = 21.896*10^-6 μM

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5 0
2 years ago
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