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nalin [4]
2 years ago
5

You are conducting an experiment inside a train car that may move along level rail tracks. A load is hung from the ceiling on a

string. The load is not swinging, and the string is observed to make a constant angle of 45∘ with the horizontal. No forces other than tension and gravity are acting on the load. Which of the following statements are correct?Statements include: 1. The train is an inertial frame of reference. 2. The train is not an inertial frame of reference. 3. The train may be at rest. 4. The train may be moving at a constant speed in a straight line. 5.The train may be moving at a constant speed in a circle. 6. The train must be speeding up. 7. The train must be slowing down. 8. The train must be accelerating.
Physics
1 answer:
sashaice [31]2 years ago
8 0

Answer:

correct answers will be

2. The train is not an inertial frame of reference.

5.The train may be moving at a constant speed in a circle.

8. The train must be accelerating.

Explanation:

As we know that string makes an angle with the horizontal

so we can write the force equation for the given ball

F_x = Tcos\theta

ma = Tcos45

also in Y direction

mg = Tsin45

now we have

\frac{ma}{mg} = cot 45

a = g cot45

now we can conclude that train is accelerating with acceleration same as gravity

now correct answers will be

2. The train is not an inertial frame of reference.

5.The train may be moving at a constant speed in a circle.

8. The train must be accelerating.

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The object moves by uniform circular motion due to the presence of a force (called centripetal force) pointing toward the center of the circle. Due to the presence of this force, the object experiences an acceleration (called centripetal acceleration) that makes the object turning in a circle. This centripetal acceleration changes only the direction of the velocity of the object, not its magnitude, which is called tangential speed and it is constant.</span>
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A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate
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To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

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Q = Heat transfer

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According to the data given we have to,

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On the other hand,

\Delta S_{source} = \frac{Q_{source}}{T_{source}}

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Therefore the work in the system is 100000Btu

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Oksana_A [137]

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\frac{dT}{dt} \alpha (T-21)\\\\\frac{dT}{dt} = k (T-21)\\\\\frac{dT}{T-21} = kdt\\\\\int\limits {\frac{dT}{T-21}}  =  \int\limits kdt\\\\Log(T-21) =kt +  Logc \\\\Log (\frac{T-21}{c} ) = kt\\\\T -21 = ce^{kt}\\\\At \ t = 0, T = 95\\\\95-21 = ce^0\\\\74 = c\\\\New, equation: T -21 = 74e^{kt}\\\\Again; when \ t= 5\ min, T = 80\\\\80 -21 = 74e^{5k}\\\\59 = 74e^{5k}\\\\e^{5k} = \frac{59}{74}\\\\ 5k = ln(\frac{59}{74})\\\\5k = -0.2265\\\\k = -0.0453

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Therefore, when the temperature of the coffee is 50 °C, the time will be 20.68 mins

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