His answer was incorrect because according to ohm's law the formula used should have been R=V/I instead of multiplying and the answer should be 8ohms
Answer:
by using formula F=ma which is m stand for mass a stand for acceleration. so 500kg × 2 ms^-2
Answer: there are 15 coins of $2 and 18 coins of $5
Explanation:
I will answer in English.
X is the number of $5 coins.
Y is the number of $2 coins.
We have the system of equations:
Y + X = 33
Y*2 + X*5 = 120
first, we must isolate one of the variables in one of the equations and then replace it in the other equation, let's isolate Y in the first equation:
Y = 33 - X.
Then we can replace it in the other equation:
(33 - X)*2 + X*5 = 120
66 - X*2 + X*5 = 120
X*3 = 54
X = 54/3 = 18
and using the equation for Y.
Y = 33 - X = 33 - 18 = 15
So there are 15 coins of $2 and 18 coins of $5
Answer:
Part A - 3N/m
Part B - see attachment
Part C - 4.9 × 10-³J
Part D - E = 1/2kd² + 1/2mv² + mgh
Explanation:
This problem requires the knowledge of simple harmonic motion for cimplete solution. To find the spring constant in part A the expression relating the force applied to a spring and the resulting stretching of the spring (hooke's law) is required which is F = kx.
The free body diagram can be found in the attachment. Fp(force of pull), Ft(Force of tension) and W(weight).
The energy stored in the pring as a result of the stretching of d = 5.7cm is 1/2kd².
Part D
Three forces act on the spring-monkey system and they do work in different forms: kinetic energy 1/2mv² , elastic potential
energy due to the restoring force in the spring or the tension force 1/2kd², and the gravitational potential energy mgh of the position of the system. So the total energy of the system E = 1/2kd² + 1/2mv² + mgh.
Answer:
The flux through the surface of the cube is 
Solution:
As per the question:
Edge of the cube, a = 8.0 cm = 
Volume Charge density, 
Now,
To calculate the electric flux:
(1)
where
= electric flux
= permittivity of free space
Volume Charge density for the given case is given by the formula:
(2)
Volume of cube, 
Thus

Thus from eqn (2), the total charge is given by:


Now, substitute the value of 'q' in eqn (1):
