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Anarel [89]
2 years ago
15

Stu wanted to calculate the resistance of a light bulb connected to a 4.0 V battery, with a resulting current of 0.5 A. He used

the formula R = VI and obtained an answer of 2 Ω. Was Stu’s answer correct? How do you know?
Physics
2 answers:
Dimas [21]2 years ago
4 0
His answer was incorrect because according to ohm's law the formula used should have been R=V/I instead of multiplying and the answer should be 8ohms
Mashutka [201]2 years ago
4 0

Answer:

Sample Response: Stu's answer was incorrect. According to Ohm's law, R = V/I. This is the equation that should be used to obtain the correct answer, which is 8 ohms.

Explanation:

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Why must the height of the meniscus in the graduated cylinder match the height of the water in the tub when measuring volume?
galben [10]

Answer:

See explanation

Explanation:

First, in order for you to understand, remember the basic concept of meniscus in graduated cylinder.

<em>"The meniscus is the curve seen at the top of a liquid in response to its container. The meniscus can be either concave or convex, depending on the surface tension of the liquid and its adhesion to the wall of the container".</em>

Now, according to this definition, and for water, the reading of the volume must be donde at the bottom of the curve of the meniscus. This is because the water  gives a concave curve.

If you read it and matches the height of water, you are getting two results:

One, get an accurate value or volume, because it's been done at eye level.

The second fact is that when you do the reading this way, The total pressure is made equal to the atmospheric pressure by adjusting the height of the cylinder until the water level is equal.

8 0
2 years ago
An object of mass M is dropped near the surface of Earth such that the gravitational field provides a constant downward force on
marysya [2.9K]

Answer:

The answer is: c. It does not move

Explanation:

Because the gravitational force is characterized by being an internal force within the Earth-particle system, in this case, the object of mass M. And since in this system there is no external force in the system, it can be concluded that the center of mass of the system will not move.

6 0
2 years ago
A professor's office door is 0.99 m wide, 2.2 m high, 4.2 cm thick; has a mass of 27 kg, and pivots on frictionless hinges. A "d
ANEK [815]

Answer:

I=8.8209\ kg.m^2

\alpha=0.6348\ rad.s^{-2}

Explanation:

Given:

  • width of door, w=0.99\ m
  • height of the door, h=2.2\ m
  • thickness of the door, t=4.2\ cm
  • mass of the door, m=27\ kg
  • torque on the door, \tau=5.6\ N.m

<em>∵Since the thickness of the door is very less as compared to its other dimensions, therefore we treat it as a rectangular sheet.</em>

  • For a rectangular sheet we have the mass moment of inertia inertia as:

I=\frac{1}{3} m.w^2

I=\frac{1}{3}\times 27\times 0.99^2

I=8.8209\ kg.m^2

We have a relation between mass moment of inertia, torque and angular acceleration as:

\alpha=\frac{\tau}{I}

\alpha=\frac{5.6}{8.8209}

\alpha=0.6348\ rad.s^{-2}

6 0
2 years ago
A reflecting telescope is built with a 20-cm-diameter mirror having a 1.00 m focal length. it is used with a 10× eyepiece.
kondaur [170]
I really wish I could be helping you. I don't know.
3 0
2 years ago
A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the
AleksAgata [21]

Answer:

acceleration = 2.4525‬ m/s²

Explanation:

Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²

Tension in the rope = T

Sol: m2 > m1

i) for downward motion of m2:

m2 a = m2 g - T

5 a = 5 × 9.81 m/s² - T  

⇒ T = 49.05‬ m/s² - 5 a     Eqn (a)‬

ii) for upward motion of m1

m a = T - m1 g

3 a = T - 3 × 9.8 m/s²

⇒ T =  3 a + 29.43‬ m/s²   Eqn (b)

Equating Eqn (a) and(b)

49.05‬ m/s² - 5 a = T =  3 a + 29.43‬ m/s²

49.05‬ m/s² - 29.43‬ m/s² = 3 a + 5 a

19.62 m/s² = 8 a

⇒ a = 2.4525‬ m/s²

5 0
2 years ago
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