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Hoochie [10]
2 years ago
7

A 0.5-kg ball accelerated at 50 m/s2 . What force was applied?

Physics
1 answer:
slega [8]2 years ago
5 0
The answer will be 25n because force equals mass times acceleration

f=m * a

.5  *  50m/s2

=25n
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A particle is moving along the x-axis. Its position as a function of time is given as x=bt-ct^2a) What must be the units of the
lisabon 2012 [21]

Answer:

We are given x= bt +ct²

So

A. bxt= m

Because m/s*s= m

So b= m/s and c= m/s²

B.

x= bt-ct²

So at x=0 t=0

x=0 t= 2

We have

bt = ct² so t = b/c at x= 0

So b-2ct= 0

B. To find velocity we use

dx / dt = b - 2 Ct

C. At rest wen V= 0

We have t= b/2c

D. To find acceleration we use

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2 years ago
Learning Goal: How do 2 ordinary waves build up a "standing" wave? A very generic formula for a traveling wave is: y1(x,t)=Asin(
zheka24 [161]

Answer:

Explanation:

=Asin(kx−ωt). This general mathematical form can represent the displacement of a string, or the strength of an electric field, or the height of the surface of water, or a large number of other physical waves!

Part C Find ye(x) and yt(t). Remember that yt(t) must be a trig function of unit amplitude. Express your answers in terms of A, k, x, ω, and t. Separate the two functions with a comma. Use parentheses around the argument of any trig functions.

Part E At the position x=0, what is the displacement of the string (assuming that the standing wave ys(x,t) is present)? Part G From

Part F we know that the string is perfectly straight at time t=π2ω. Which of the following statements does the string's being straight imply about the energy stored in the strJHJMNMMUJJHTGGHing?

a.There is no energy stored in the string: The string will remain straight for all subsequent times.

b.Energy will flow into the string, causing the standing wave to form at a later time.

c.Although the string is straight at time t=π2ω, parts of the string have nonzero velocity. Therefore, there is energy stored in the string.

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3 0
2 years ago
An egg falls from a nest at a height of 4m. What speed will it have when it is 1m from the ground? Neglect air resistance and ta
Zolol [24]

Answer: 7.66 m/s

Explanation:

This situation is related to free fall (vertical motion). Hence, this can be considered a one-dimension problem and we can use the following equation:

V^{2}=V_{o}^{2}+2gd

Where:

V is the final velocity of the egg at the asked height

V_{o}=0 m/s is the initial velocity of the egg

g=9.8 m/s^{2} is the acceleration due gravity

d=4 m- 1m= 3m is the distance at which the egg is from the nest, when it is 1 m from the ground

Isolating V:

V=\sqrt{V_{o}^{2}+2gd}

Substituting the known values:

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2 years ago
An object with a mass m slides down a rough 37° inclined plane where the coefficient of kinetic friction is 0.20. If the plane i
hodyreva [135]

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The Newton's law gives:

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Space

S = 0.5*a*t²

10 = 0.5*a*t²

=> t = 2.148 s

Velocity

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5 0
2 years ago
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olga55 [171]

Initial speed of the particle is

1.497\sqrt{(1/m)/(kq^{2} /d)}

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