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2 years ago

A 45.0-kg sample of ice is at 0.00°C. How much heat is needed to melt it? For water, Lf=334 kJ/kg and Lv=2257 kJ/kg

Physics

2 answers:

Aleonysh [2.5K]2 years ago

7 0

Heat required to change the phase of ice is given by

Q = m* L

here

m = mass of ice

L = latent heat of fusion

now we have

m = 45 kg

L = 334 KJ/kg

now by using above formula

$Q = 45 * 334 * 10^3$

$Q = 1.5 * 10^7 J$

In KJ we can convert this as

$Q = 1.5 * 10^4 kJ$

so the correct answer is D option

Vlad1618 [11]2 years ago

6 0

H=ml
H=334×45.0
Heat Energy= 15030kJ

or 1.50×10^4kJ

answer: D

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2 years ago

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sasho [114]

We use the kinematic equations,

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2 years ago

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2 years ago

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Answer:

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