An electric pump rated 1.5 KW lifts 200kg of water through a vertical height of 6m in 10 secs: way is the efficiency of the pump
1 answer:
Answer:
80%
Explanation:
Efficiency = Power output / Power input × 100 %
To calculate efficiency we need to find power output of electric pump.
We can use,
Work done = Energy change
Work done per second = Energy change per second
Work done per second = Power
Therefore, Power = Energy change per second
= Change in potential energy of water per second
=mgh / t
= 200× 10×6 / 10
= 1200 W = 1.2 kW
Now use the first equation to find efficiency,
Efficiency = × 100%
= 80 %
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Answer:C
Explanation:
It is given that hand strap moves from the vertical in the backward direction.
The direction of strap depends upon the acceleration of bus i.e. if bus is accelerating in forward direction then strap will move in backward direction and vice-versa.
The reason for moving backwards is due to the psuedo acting on strap which bends the strap in backward direction
angle of inclination is given by
where a=acceleration of bus
=inclination of strap from vertical
so we cannot conclude anything about the direction of the velocity of the bus