Question

A high school theater club has 40 students, of whom 6 are left-handed. Two students from the club will be selected at random, one at a time without replacement. What is the probability that the 2 students selected will both be left-handed?

Answer 1

Answer:

$1.92\%$

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

$P=\frac{x}{y}$

Find out the probability that the first student selected will be left-handed

we have

$x=6$

$y=40$

substitute

$P=\frac{6}{40}$

Simplify

$P=\frac{3}{20}$

Find out the probability that the second student selected will be left-handed

we have

$x=6-1=5$

$y=40-1=39$

substitute

$P=\frac{5}{39}$

Find out the probability that the 2 students selected will both be left-handed

Multiply the probabilities

$P=\frac{3}{20}(\frac{5}{39})=\frac{15}{780}$

Convert to percentage

Multiply by 100

$\frac{15}{780}(100)=1.92\%$