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hram777 [196]
1 year ago
6

Grandpa ernie is shrinking! Over the past 4 years, his hight decressed by a total of 2.4cm. It decresed by the same amount each

year. What was the change in grandpa ernies hight eac year?
Mathematics
2 answers:
alexandr402 [8]1 year ago
5 0

Answer:

-0.6cm

Step-by-step explanation:

just got it wrong cause da guy in front of meh

dolphi86 [110]1 year ago
4 0

Answer: 0.6 cm

Step-by-step explanation:

Given : Over the past 4 years, Grandpa Ernie's height decreased by a total of 2.4 cm.

If  the height is decreased by the same amount each year.

Then, the change in Grandpa Ernie's height each year will be =

Total decrease in height ÷ 4

= 2.4 cm  ÷  4  = 0.6 cm

Hence, the  change in Grandpa Ernie's height each year = 0.6 cm

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Vicky's checking account charges a $12.25 monthly service fee and a $0.26
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Remove perfect cubes from under the radical and combine like terms.

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Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start
Kamila [148]

Option B: \frac{1}{(m-4)(m-3)} is the correct answer.

Explanation:

The given expression is \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}

Simplifying the expression, we have,

\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}

Factor the equations, m^{2}-16\right and m^{2}-9,we get,

m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)

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Substituting these factored expressions in the above expression, we have,

\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}

Cancelling the common terms m+3 and m+4 , we get,

\frac{1}{(m-4)(m-3)}

Thus, the expression equivalent to \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )} is \frac{1}{(m-4)(m-3)}

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