All categories

2 years ago

In the first week

Mathematics

1 answer:

FromTheMoon [43]2 years ago

8 0

The percent change in the number of people who went to the pool

between the first and last week is 10% less

Step-by-step explanation:

The given is:

In the first week of July, a record 1,060 people went to the local swimming pool
In the second week, 105 fewer people went to the pool
In the third week, 135 more people went to the pool than in the second week
In the fourth week, 136 fewer people went to the pool than in the third week

We need to find the percent change in the number of people who

went to the pool between the first and last weeks

∵ There were 1060 people in the 1st week

∵ There were 105 fewer people in the 2nd week

∴ The number of people in the 2nd week = 1060 - 105 = 955

∴ There were 955 people in the 2nd week

∵ There were 135 more people in the 3rd week than the 2nd week

∵ There were 955 people in the 2nd week

∴ The number of people in the 3rd week = 955 + 135 = 1090

∴ There were 1090 people in the 3rd week

∵ There were 136 fewer people in the 4th week than in the 3rd week

∵ There were 1090 people in the 3rd week

∴ The number of people in the 4th week = 1090 - 136 = 954

∴ There were 954 people in the 4th week

Let us find the change from 1st week to last week

∵ There were 1060 people in the 1 st week

∵ There were 954 people in the last week

∴ The change = 1060 - 954 = 106

∵ Percent change = $\frac{Change}{Original}$ × 100%

∴ Percent change = $\frac{106}{1060}$ × 100%

∴ Percent change = 10%

The percent change in the number of people who went to the pool

between the first and last week is 10% less

Learn more:

You can learn more about percentage in brainly.com/question/12501490

#LearnwithBrainly

You might be interested in

A researcher gathers data on the length of essays (number of lines) and the SAT scores received for a sample of students enrol

LenaWriter [7]

Answer:

Step-by-step explanation:

Let's suppose that we have the following linear model:

$y= \beta_o +\beta_1 X$

Where Y is the dependent variable and X the independent variable. $\beta_0$ represent the intercept and $\beta_1$ the slope.

In order to estimate the coefficients $\beta_0 ,\beta_1$ we can use least squares estimation.

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: $\beta_1 = 0$

Alternative hypothesis: $\beta_1 \neq 0$

Or in other wouds we want to check is our slope is significant.

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal

The significance level is provided and on this case is $\alpha=0.05$

The standard error for the slope is given by this formula:

$SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}$

Th degrees of freedom for a linear regression is given by $df=n-2$ since we need to estimate the value for the slope and the intercept.

In order to test the hypothesis the statistic is given by:

$t=\frac{\hat \beta_1}{SE_{\beta_1}}$

The confidence interval for the slope would be given by this formula:

$\hat \beta_1 + t_{n-2, \alpha/2} \frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}$

And using the last formula we got that the confidence interval for the slope coefficient is given by:

$-0.88 < \beta_1$

IF we analyze the confidence interval contains the value 0. So we can conclude that we don't have a significant effect of the slope on this case at 5% of significance. And the best option would be:

6 0

2 years ago

Find the value of z such that 0.9722 of the area lies between −z and z. Round your answer to two decimal places.

Amiraneli [1.4K]

Answer:

-2.20 < z < 2.20

Step-by-step explanation:

You are saying the entire area = 0.9722

so 1 - 0.9722 = 0.0278

then we want it to fit in the middle of the normal curve with center 0

so...

0.0278/2 =0.0139 this corresponds to 2.20 on the z-score chart

7 0

2 years ago

Which of the following uses estimation to check 267 – 154 = 113?

Arturiano [62]

Estimation is taking the general values of an equation to find an answer that is close to the actual answer.

Round the numbers in the equation to their tens places by checking their ones value:

267
7 > 5
267 -> 270

154
4 < 5
154 -> 150

Subtract these two rounded values:

$270 - 150 = 120$

The answer that has this equation is D.

5 0

2 years ago

Workers need to know the area of a park to determine how much grass seed to order. A worker drew a sketch of the park to find it

MatroZZZ [7]

The area of the park is 1465m squared, because you would find the area of the square first which is 100m squared and then you would add that to the area of the trapezoid which is 1365m squared and after you add them, you would get 1465m squared. I’m still not sure if this is the exact answer but please check it over to see if I did it correct :)

4 0

2 years ago

Read 2 more answers

320miles on 34 gallons in simplest form

Alborosie

Answer:

9 and 2/5 gallons

Step-by-step explanation:

34 x 9 gallons = 306 miles

14 / 34 = 4/10 of the gallons

4/10 simplified = 2/5

Answer: 9 2/5