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NNADVOKAT [17]
2 years ago
14

Two cables of the same length are made of the same material, except that one cable has twice the diameter of the other cable. Wh

en the same potential difference is maintained across both cables, which of the following statements are true? (There may be more than one correct choice.)
1.The same current flows through both cables.
2. The current in the thin cable is four times as great as the current in the thick cable.
3. The current in the thin cable is twice as great as the current in the thick cable.
4. Both cables carry the same current density.
5. The electrons have the same drift velocity in both cables.
Physics
1 answer:
belka [17]2 years ago
6 0

Answer: The same current flows through bth cables

Explanation:

Lets have a look to the next two equations

The Ohm´s     V = I*R    (1)

where:

V is voltage (potencial dfference) in volts

I is the electric current in ampers

R is the electric resistance

When a voltage is applied as the electrc load is not specified ( we have to assume is the same) the current will be the same

And in the other hand the resistance  R =ρL/s

Where  ρ is the resistivity of the conductor  L the length and s square section of the conductor

If we assume that the smaller diameter cable is able to conduct the current then nothing happens. The point is that the capacity of conduction of current depend on the section of the cable (the area)

Tables exist where to find the capacity of each cable according to its diameter.

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At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²

Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s

Point 2 (stagnation):
At the stagnation point, the velocity is zero.

The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
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Answer: 2.2 psi

5 0
2 years ago
The gas tank of Dave’s car has a capacity of 12 gallons. The tank was 38 full before Dave filled it to capacity. It cost him $2.
m_a_m_a [10]

Answer:

$ 18.75            

Explanation:

given,                                              

capacity of the Dave’s car = 12 gallons

Assuming that the tank is 3/8 full before

Cost of gas per gallon =  $2.50 per gallon of gas

Volume Dave have to fill                      

       =1 - \dfrac{3}{8}                          

       =\dfrac{5}{8} of full tank              

       =\dfrac{5}{8}\times 12              

volume Dave have to fill = 7.5 gallons          

total money Dave spent                  

     = 7.5 gallons x $2.50                

     = $ 18.75                                            

Dave have to spend $ 18.75 to fill tank to it capacity.

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2 years ago
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A healthy astronaut's heart rate is 60 beats/min. Flight doctors on Earth can monitor an astronaut's vital signs remotely while
Anton [14]
GIVEN:
   60 beats per minute
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   find x= how fast would an astronaut be flying away
 1            x
-----   *  ------ = (60x = 21)  -------> 60x = 21    ------------>  x= 0.35 
60         21                                  -------   -----
                                                     60      60

The answer is 0.35 seconds which refers to how fast would an astronaut be flying away from the earth if he has a heart rate of 21 beats/min. 
5 0
2 years ago
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A student bikes to school by traveling first dN = 1.00 miles north, then dW = 0.600 miles west, and finally dS = 0.200 miles sou
kompoz [17]
Refer to the diagram shown below.

Define unit vectors along the x and y axes as respectively \hat{i} \, and \, \hat{j}.

Then the three successive displacements, written in component form, are respectively
\vec{dN} = 1.0 \, \hat{j} \\
\vec{dW} = -0.6 \, \hat{i} \\  \vec{dS} = -0.2 \, \hat{j}

The total displacement for the first leg of the trip is
\vec{d} = \vec{dN} + \vec{dW} + \vec{dS} \\ \vec{d}= 1.0\hat{j}-0.6\hat{i}-0.2\hat{j} \\ \vec{d}=-0.6\hat{i}+0.8\hat{j}

Answer:
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2 years ago
You throw a tennis ball (mass 0.0570 kg) vertically upward. It leaves your hand moving at 15.0 m/s. Air resistance cannot be neg
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Answer:195 J

Explanation:

Given

mass of ball m=0.0570\ kg

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maximum height reached by ball h=8\ m

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M.E._1=6.41\ J

Mechanical Energy at highest point

(M.E.)_2=(P.E.+K.E.)_2

at highest Point velocity is zero

(M.E.)_2=mgh_2+0

(M.E.)_2=0.0570\times 9.8\times 8

(M.E.)_2=4.46\ J

Decrease in Mechanical energy

(M.E.)_1-(M.E.)_2=6.41-4.46

(M.E.)_1-(M.E.)_2=1.95\ J

3 0
2 years ago
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