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NNADVOKAT [17]
2 years ago
14

Two cables of the same length are made of the same material, except that one cable has twice the diameter of the other cable. Wh

en the same potential difference is maintained across both cables, which of the following statements are true? (There may be more than one correct choice.)
1.The same current flows through both cables.
2. The current in the thin cable is four times as great as the current in the thick cable.
3. The current in the thin cable is twice as great as the current in the thick cable.
4. Both cables carry the same current density.
5. The electrons have the same drift velocity in both cables.
Physics
1 answer:
belka [17]2 years ago
6 0

Answer: The same current flows through bth cables

Explanation:

Lets have a look to the next two equations

The Ohm´s     V = I*R    (1)

where:

V is voltage (potencial dfference) in volts

I is the electric current in ampers

R is the electric resistance

When a voltage is applied as the electrc load is not specified ( we have to assume is the same) the current will be the same

And in the other hand the resistance  R =ρL/s

Where  ρ is the resistivity of the conductor  L the length and s square section of the conductor

If we assume that the smaller diameter cable is able to conduct the current then nothing happens. The point is that the capacity of conduction of current depend on the section of the cable (the area)

Tables exist where to find the capacity of each cable according to its diameter.

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<h3><u>Answer;</u></h3>

<em>Work = 125 joules </em>

<h3><u>Explanation and solution</u>;</h3>
  • Work is the product of force and the distance covered. Therefore, Work = force × distance.
  • Work is measured in joules.
  • Work is also a change in energy, such that work is done when energy changes, so when kinetic energy, or potential energy changes the there is work being done.

Thus; kinetic energy = work done

Kinetic energy = 1/2mv²

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A box of mass 8 kg slides across a frictionless surface at an initial speed 1.5 m/s into a relaxed spring of spring constant 69
Sav [38]

Answer:

1.1 sec

Explanation:

m = mass of the box = 8 kg

k = spring constant of the spring = 69 N/m

v = initial speed of the box = 1.5 m/s

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Time period is given as

t = \pi \sqrt{\frac{m}{k}}

Inserting the values

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moles H2 = 0.00922 g ( 1 mol / 2.02 g ) = 0.005 mol H2

Volume H2 at STP = 0.005 mol H2 ( 22.4 L / 1 mol ) = 0.102 L of H2
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Answer:

Hello there Dude answer is B :D hope it helped mark me brainliest.

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