Answer:
number of electrons = 2.18*10^18 e
Explanation:
In order to calculate the number of electrons that move trough the second wire, you take into account one of the Kirchoff's laws. All the current that goes inside the junction, has to go out the junction.
Then, if you assume that the current of the wire 1 and 3 go inside the junction, then, all this current have to go out trough the second junction:
(1)
i1 = 0.40 A
i2 = 0.75 A
you solve the equation i3 from the equation (1):

Next, you take into account that 1A = 1C/s = 6.24*10^18
Then, you have:

The number of electrons that trough the wire 3 is 2.18*10^18 e/s
Answer:
The speed is
.
(a) is correct option.
Explanation:
Given that,
Potential difference 
Speed 
If it were accelerated instead
Potential difference 
We need to calculate the speed
Using formula of initial work done on proton

We know that,


Put the value into the formula

....(I)
If it were accelerated instead through a potential difference of
, then it would gain a speed will be given as :
Using an above formula,

Put the value of 



Hence, The speed is
.
Answer:
Milliliters to Ounces Conversions
some results rounded
mL - fl oz
200.00 6.7628
200.01 6.7631
200.02 6.7635
200.03 6.7638
200.04 6.7642
200.05 6.7645
200.06 6.7648
200.07 6.7652
200.08 6.7655
200.09 6.7658
200.10 6.7662
200.11 6.7665
200.12 6.7669
200.13 6.7672
200.14 6.7675
200.15 6.7679
200.16 6.7682
200.17 6.7686
200.18 6.7689
200.19 6.7692
200.20 6.7696
200.21 6.7699
200.22 6.7702
200.23 6.7706
200.24 6.7709
mL fl oz
200.25 6.7713
200.26 6.7716
200.27 6.7719
200.28 6.7723
200.29 6.7726
200.30 6.7729
200.31 6.7733
200.32 6.7736
200.33 6.7740
200.34 6.7743
200.35 6.7746
200.36 6.7750
200.37 6.7753
200.38 6.7757
200.39 6.7760
200.40 6.7763
200.41 6.7767
200.42 6.7770
200.43 6.7773
200.44 6.7777
200.45 6.7780
200.46 6.7784
200.47 6.7787
200.48 6.7790
200.49 6.7794
mL fl oz
200.50 6.7797
200.51 6.7800
200.52 6.7804
200.53 6.7807
200.54 6.7811
200.55 6.7814
200.56 6.7817
200.57 6.7821
200.58 6.7824
200.59 6.7828
200.60 6.7831
200.61 6.7834
200.62 6.7838
200.63 6.7841
200.64 6.7844
200.65 6.7848
200.66 6.7851
200.67 6.7855
200.68 6.7858
200.69 6.7861
200.70 6.7865
200.71 6.7868
200.72 6.7872
200.73 6.7875
200.74 6.7878
mL fl oz
200.75 6.7882
200.76 6.7885
200.77 6.7888
200.78 6.7892
200.79 6.7895
200.80 6.7899
200.81 6.7902
200.82 6.7905
200.83 6.7909
200.84 6.7912
200.85 6.7915
200.86 6.7919
200.87 6.7922
200.88 6.7926
200.89 6.7929
200.90 6.7932
200.91 6.7936
200.92 6.7939
200.93 6.7943
200.94 6.7946
200.95 6.7949
200.96 6.7953
200.97 6.7956
200.98 6.7959
200.99 6.7963
Explanation:
Answer:
towards left
Explanation:
As we know that there is no external force on the system of two cart so total momentum of the system is conserved
so we will say

now plug in all data into the above equation

here we assumed that left direction of motion is negative while right direction is positive
so we can solve it for speed v now



Answer:(a) 50 N
(b)38.34 N
Explanation:
Given
Maximum tension(T) in line 50 N
(a)If line is moving up with constant velocity i.e. there is no acceleration
This will happen when Tension is equal to weight of Fish
T-mg=0
T=mg
Maximum weight in this case will be 50 N
(b)acceleration of magnitude 
T-mg=ma


m=3.91
Therefore weight is 