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Arturiano [62]
2 years ago
8

If Mary drove 525miles in 7hours at an average speed of 75 miles per hour how much faster would her average speed need to be to

make the trip in 5 hours ( a little speed demon!)
Chemistry
1 answer:
Makovka662 [10]2 years ago
6 0
<h3>Answer:</h3>

30 miles per hour faster

<h3>Explanation:</h3>

We are given;

  • Distance that Mary drove as 525 miles
  • Time she took as 7 hours
  • Average speed as 75 miles per hour

We are supposed to determine how fast the average speed would be if she made the trip in 5 hours.

  • We know that speed is given by dividing distance by time taken.
  • In this case distance remained constant

Therefore, we can determine the speed when she took 5 hours

  • Speed = Distance ÷ time

           = 525 miles ÷ 5 hours

           = 105 hours

Thus, the new speed would be 105 miles per hours

But, initial speed was 75 miles per hour

Therefore, she would travel 30 miles per hour faster to cover the journey in 5 hours.

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According to periodic properties, what would be the most likely formula for the product obtained when Lv reacts with H2(g)?
svetoff [14.1K]

Answer:

H₂Lv

Explanation:

Lv is at group 6 on the periodic table, so it has 6 valence electrons, likely oxygen. Thus, to be stable, it needs to gain 2 electrons. Hydrogen has 1 electron in its valence shell, so H₂ can share 2 electrons with Lv, and because of that, the product would be:

H₂Lv.

5 0
2 years ago
Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide
olya-2409 [2.1K]

Answer:

     strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

     X^{+} will oxidize Z

Explanation:

The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.

Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.

Order of reduction potential:

                       E_{X^{+}\mid X}^{0}(1.52V)> E_{Z^{3+}\mid Z}^{0}(0.84V)> E_{Y^{2+}\mid Y}^{0}(-1.17V)

So, strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

As reduction potential of the half cell X^{+}\mid X is higher than the reduction potential of the half cell Z^{3+}\mid Z therefore X^{+} will oxidize Z into Z^{3+} and itself gets converted into X.

     

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What are the intermolecular forces between molecules in a liquid sample of sulfur trioxide,SO3?a. hydrogen bonding b. dipole-dip
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Answer:

dispersion forces

Explanation:

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The primary intermolecular force in nonpolar molecules is the London dispersion forces. As expected, the London dispersion forces is the intermolecular force present in SO3.

Hence SO3 is a symmetrical molecule having only weak dispersion forces acting between its molecules.

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Describe two shortcomings of the pennium model for isotopes
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In an experiment, 4.14 g of phosphorus combined with chlorine to produce 27.8 g of a white solid compound. what is the empirical
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Grams of Phosphorus = 4.14 grams 
Grams of white compound = 27.8 grams 
Grams of Chlorine would be = 27.8 - 4.14 = 23.66 grams
 Calculating moles which would be grams / molar mass
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 Calculating the ratios by dividing with the small entity
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 Cl = 0.6674 moles / 0.1337 moles = 5 
So the empirical formula would be PCl5
3 0
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