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juin [17]
2 years ago
11

An object of mass 5 kilograms is moving across a surface in a straight line with a speed of 3.5 meters/second. What amount of fo

rce would be required to keep the object in motion if you ignore the surface friction?
Physics
1 answer:
jek_recluse [69]2 years ago
7 0
F = MA 
A = change in velocity 
Constant velocity = no change in velocity = Zero acceleration 
<span>Ignoring friction, 5 kg * 0 m/s^2 = 0 N 
</span>
Therefore, there is no force (0 N) required to keep the object in motion if the surface friction is ignored.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is reese (enr647) – HS OnRamps 04
icang [17]

Answer:

W = 0 J

Explanation:

It is given that,

Weight of the crate, W = 100 N

Distance moved by the crate, d = 1.5 m

Let W is the work done to hold the crate 1.5 m above the ground in this way. It is given by the product of force and the displacement. Its formula is given by :

W=F\times d\times cos\theta

Here, \theta=90^{\circ} as it is lifted vertically

W=100\ N\times 1.5\ m\ cos(90)      

W = 0

So, the work done to hold the crate is 0. Hence, this is the required solution.

5 0
2 years ago
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Is the statement "An object always moves in the direction of the net force acting on it" true or false
Trava [24]

Answer:

False

Explanation:

This is because according to newtons second law which says the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. So take for example a net a net force in opposite direction will cause an object to slow down.

velocity vector here is not the same as acceleration vector

7 0
2 years ago
At a given point on a horizontal streamline in flowing air, the static pressure is â2.0 psi (i.e., a vacuum) and the velocity is
Nastasia [14]
At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²

Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s

Point 2 (stagnation):
At the stagnation point, the velocity is zero.

The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
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Answer: 2.2 psi

5 0
2 years ago
Consider a father pushing a child on a playground merry-go-round. the system has a moment of inertia of 84.4 kg · m2. the father
-Dominant- [34]
<span>At time t1 = 0 since the body is at rest, the body has an angular velocity, v1, of 0. At time t = X, the body has an angular velocity of 1.43rad/s2. Since Angular acceleration is just the difference in angular speed by time. We have 4.44 = v2 -v1/t2 -t1 where V and t are angular velocity and time. So we have 4.44 = 1.43 -0/X - 0. Hence X = 1.43/4.44 = 0.33s.</span>
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Which of the following is not a factor in whether a reaction will spontaneously occur? A. Entropy change of the system B. Enthal
Delvig [45]

Answer:

D

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