Question

2. Given the coordinates, classify triangle QRT by its sides. Q(-2, -1), R(1,5), T(-8,-4)

Answer 1

Answer:

The measure of sides of triangle with given points are

QR = 3$\sqrt{5}$  unit

RT = 9$\sqrt{2}$  unit

TQ =  $\sqrt{13}$  unit

Step-by-step explanation:

Given as :

The coordinate of Triangle QRT as :

Q = ( - 2 , - 1 )

R = ( 1 , 5 )

T = ( - 8 , - 4 )

Now , The Distance between the points can be measure as :

QR = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, QR =  $\sqrt{(1+2)^{2}+(5+1)^{2}}$

Or, QR = $\sqrt{(3)^{2}+(6)^{2}}$

Or, QR = $\sqrt{45}$ = 3$\sqrt{5}$  unit

Similarly

RT =  $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, RT =  $\sqrt{(-8-1)^{2}+(-4-5)^{2}}$

Or,  RT =  $\sqrt{(-9)^{2}+(-9)^{2}}$

Or, RT =  $\sqrt{162}$ = 9$\sqrt{2}$  unit

And

TQ =  $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, TQ =  $\sqrt{(-2+8)^{2}+(-1+4)^{2}}$

Or, TQ = $\sqrt{(2)^{2}+(3)^{2}}$

Or, TQ = $\sqrt{13}$  unit

Hence The measure of sides of triangle with given points are

QR = 3$\sqrt{5}$  unit

RT = 9$\sqrt{2}$  unit

TQ =  $\sqrt{13}$  unit         Answer