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denpristay [2]
1 year ago
7

Two students are looking at a brightly lit full Moon, illuminated by the reflected light from the Sun. Consider thefollowing dis

cussion between the two students about what the spectrum of moonlight would look like.Student
1: I think that moonlight is just reflected sunlight, so we will see the Sun’s absorption line spectrum.Student
2: I disagree.An absorption spectrum has to come froma hot, dense object. Since the Moon is not a hot, dense object, it can’t give off an aborption line spectrum.Do you agree or disagree with either or both of the students
Physics
1 answer:
BartSMP [9]1 year ago
3 0

Answer:

I agree with the student that think that moonlight is just reflected sunlight, so we will see the Sun’s absorption line spectrum.

Explanation:

Absorption spectrums occur when a white light is passed through a gas. Or simply a light from a hot source passes through a cooler gas. The moon itself is a reflection of the sun, so when it reflects the light from the sun, absorption spectrum lined can be seen. Note that it is the hot gases like hydrogen, oxygen etc in or around the sun that cause absorption spectrum.

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A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and
snow_tiger [21]

Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

Mass of child = 27 kg

Speed of child in horizontal = 10 m/s

Length = 3.40 m

There is a rate of change of the perpendicular component of momentum.

Centripetal force acts always towards the center.

We need to calculate the magnitude of the rate of change of the child's momentum

Using formula of momentum

\dfrac{dp}{dt}=F

\dfrac{dP}{dt}=\dfrac{mv^2}{r}

Put the value into the formula

\dfrac{dP}{dt}=\dfrac{27\times10^2}{3.40}

\dfrac{dP}{dt}=794.11\ N

Hence, The magnitude of the rate of change of the child's momentum is 794.11 N.

7 0
2 years ago
Which common gas is less abundant in the top of saturn's atmosphere, compared to what we observe at jupiter?
Lera25 [3.4K]
This would be helium; the reason for this is unknown but one thery states that the helium might have condensed in form of rain and sank to the lower region of the atmosphere
8 0
2 years ago
Two teams are pulling a heavy chest, located at point X. The teams are 4.6 meters away from each other. Team A is 2.4 meters awa
Sladkaya [172]
For a better understanding of the question, please see attached picture that I've created.
We need to identify the other two angles by applying the Law of sine where we are given with the following values:
a = 3.2 unit
b = 2.4 unit
c = 4.6 unit
∠A = unknown
∠B = unknown
∠C = 110°

Solving for ∠B, we have:
sin C / c = sin B / b
sin 110 / 4.6 = sin B / 2.4
sin B = 2.4*sin 110 / 4.6
B = 29.36°

Solving for ∠A, we have:
sinC/c = sinA/ a
sin110 / 4.6 = sinA / 3.2
sinA = 3.2*sin110/ 4.6
A = 40.82°

Therefore, the missing angles are ∠A=40.82° and ∠B=29.36°.

3 0
2 years ago
Read 2 more answers
The Richter scale measures the __ of an earthquake.<br>​
IRISSAK [1]

Answer:  maximum amplitude of seismic waves as they reach seismographs. So the category the earthquake is such as a 6.0 or a 7.0.

Explanation:

8 0
1 year ago
Read 2 more answers
The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an
balandron [24]

Answer:

a)  f = 3400 Hz , b)  f5 = 17000 Hz , c) speed is much higher and the frequency is directly proportional to the speed so  the frequency increases

Explanation:

The resonance in a system with one end closed and the other open, we can find it because in the closed points we have nodes and in the open parts we have a maximum, so for this system we have the following resonances

 

    4L = λ                fundamental

    4L = 3 λ₃           third harmonic

    4L = 5 λ₅           fifth harmonic

   4L = (2n + 1)λ     general with n = 1, 2,3,

a) the speed of the wave is

              v = λ f

              f = v /λ

               

            λ₁ = 4L / 1

            λ₁ = 4 0.025 m

            λ₁ = 0.1 m

             f = 340 / 0.1

             f = 3400 Hz

b) the second resonance occurs for n = 5

           λ₅ = 4 0.025 / 5

           λ₅ = 0.02 m

           f5 = 340 / 0.02

           f5 = 17000 Hz

c) if the channel is full of water the speed of sound is v = 1436 m / s

     Since the speed is much higher and the frequency is directly proportional to the speed so  the frequency increases

d) The intensity is defined

            I = P / A

            P = I A

            P = 4.10-6 210.10-3

            P = 840 10-9 W

e) the intensity is β₁ = 110 if it is reduced by a factor of 3, Δβ = 110/3 = 36.67 f

The intensity of the system is now β₂ = 110 - 36.67 = 73.33  

We can calculate what the intensity reduction is

              β1 = 10 log (I1 / Io)

              β2 = 10 log (I2 / Io)

              β1 - β 2 = 10 [log (I1 / Io) - log (I2 / Io))

              β1 -β2 = 10 log (I1 / I2)

               I1 / I2 = 10 (β1-β2) / 10

Calculous

             I1-I2 = 10 (36.67 / 10)

             I1 / I2 = 4645

             I2 = 1/4645 I1

5 0
1 year ago
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