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2 years ago

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The ionic compounds NaClNaCl and MgSMgS are represented by the diagrams above. Which statement correctly identifies diagram 1 an

d identifies the compound with the lower melting point, explaining why?

1 answer:

Oksana_A [137]2 years ago

7 0

Answer:check explanation

Explanation:

No diagram is given above but to determine the value of melting point we need to understand the fact that NaCl has a lower melting point than MgS.

Reasons are; (1) sodium ion (+1) in the first group of the periodic table is characterized by its softness and low melting point and, (2). Is that it has a lower melting point than MgS because the COULUMBIC ATTRACTIONS between its singly charged sodium ions(+1) and the chlorine ions(-1) are weaker than those between the ions in MgS.

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Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N2O4(g) 2N

Amanda [17]

Answer : The correct option is, (a) 0.44

Explanation :

First we have to calculate the concentration of $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

Now we have to calculate the dissociated concentration of $N_2O_4$ .

The balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(aq)$

Initial conc. 1.0 M 0

At eqm. conc. (1.0-x) M (2x) M

As we are given,

The percent of dissociation of $N_2O_4$ = $\alpha$ = 28.0 %

So, the dissociate concentration of $N_2O_4$ = $C\alpha=1.0M\times \frac{28.0}{100}=0.28M$

The value of x = $C\alpha$ = 0.28 M

Now we have to calculate the concentration of $N_2O_4\text{ and }NO_2$ at equilibrium.

Concentration of $N_2O_4$ = 1.0 - x = 1.0 - 0.28 = 0.72 M

Concentration of $NO_2$ = 2x = 2 × 0.28 = 0.56 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.56)^2}{0.72}=0.44$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.44

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2 years ago

A. Use average bond energies together with the standard enthalpy of formation of C(g) (718.4 kJ/mol ) to estimate the standard e

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Answer:

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b. due to resonance, some energy are released

Explanation:

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2 years ago

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AveGali [126]

The answer is C). PH3

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2 years ago

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The name carbohydrate comes from the fact that many simple sugars have chemical formulae that look like water has simply been ad

GREYUIT [131]

Answer:

The maximum mass of water produced is $m__{H_2O}} =116 \ g$

Explanation:

From the question we are told that

The mass of sucrose is $m_s = 200 \ g$

The chemical formula for sucrose is $C_{12} H_{22} O_{11}$

The chemical equation for the dissociation of sucrose is

$C_{12} H_{22}O_{4} \to 12C + 11H_2O$

The number of moles of sucrose can be evaluated as

$n = \frac{m}{Z}$

Where Z is the molar mass of sucrose which has a constant value of

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So

$n = \frac{200}{342}$

$n =0.585$

From the chemical equation one mole of sucrose produces 11 moles of water so 0.585 moles of sucrose will produce x moles of water

Therefore

$x = \frac{0.585 * 11}{1}$

$x = 6.433 \ moles$

Now the mass of water produced is mathematically represented as

$m__{H_2O}} = x * Z__{H_2O}$

Where $Z__{H_2O}$ is the molar mass of water with a constant values of $Z__{H_2O}} = 18 \ g/mol$

So

$m__{H_2O}} = 6.43* 18$

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