A car traveling along a straight road at 71 ft/sec accelerated to a speed of 79 ft/sec over a distance of 160 ft. What was the a
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Answer:
Let's see the similarities between the two forces
* are proportional to the product of a magnitude, mass or charge
* They are inversely proportional to the square of the distance
* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.
The differences in them
* The electric force in much greater than the gravitational force
* The gravitational force is always attractive, the electrical force can be attractive or repulsive.
Explanation:
Let's start by calculating each force.
Gravitational force
F =
let's calculate
F = 6.67 10⁻¹¹ 1 1 / 1²
F = 6.67 10⁻¹¹ N
Electric force
F =
indicates that the charge is q = 10 C
F = 9 10⁹ 10 10 / 1²
F = 9 10¹¹ N
Let's see the similarities between the two forces
* are proportional to the product of a magnitude, mass or charge
* They are inversely proportional to the square of the distance
* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.
The differences in them
* The electric force in much greater than the gravitational force
* The gravitational force is always attractive, the electrical force can be attractive or repulsive.
As we know that reaction time will be
so the distance moved by car in reaction time
now the distance remain after that from intersection point is given by
So our distance from the intersection will be 100 m when we apply brakes
now this distance should be covered till the car will stop
so here we will have
now from kinematics equation we will have
so the acceleration required by brakes is -2 m/s/s
Now total time taken to stop the car after applying brakes will be given as
total time to stop the car is given as