Answer:
2s²2p⁴
Explanation:
Oxygen is an element on the periodic table with a total of 8 electrons. It's electronic configuration is given as 2,6.
Using the orbital notation we write as 1s²2s²2p⁴
Also, the valence electrons are the electrons in the outermost shell of an atom. These electrons mostly determine the chemical properties of an atom.
Oxygen has a total of 6 electrons in its outermost shell and it is given as 2s²2p⁴
Hey there !
Molar mass carbon dioxide:
CO2 = 44.01 g/mol
1) number of moles :
1 mole CO2 ------------- 44.01 g
(moles CO2) ------------ 243.6 g
moles CO2 = 243.6 * 1 / 44.01
moles CO2 = 243.6 / 44.01
=> 5.535 moles of CO2
Therefore:
1 mole -------------------- 6.02x10²³ molecules
5.535 moles ------------ ( molecules CO2)
molecules CO2 = 5.535 * ( 6.02x10²³) / 1
=> 3.33x10²⁴ molecules of CO2
Given mass of KNO₃=346g
Molar mass of KNO₃=(39.098)+(14)+(15.99*3)=101.068gmol⁻¹
Volume of Solution=750ml=0.75dm³
Molarity=(mass of solute/molar mass of solute)*(1/volume of sol. in dm³)
=(346/101.068)*(1/0.75)
=4.56 mol dm⁻³
First, let us find the corresponding amount of moles H₂ assuming ideal gas behavior.
PV = nRT
Solving for n,
n = PV/RT
n = (6.46 atm)(0.579 L)/(0.0821 L-atm/mol-K)(45 + 273 K)
n = 0.143 mol H₂
The stoichiometric calculations is as follows (MW for XeF₆ = 245.28 g/mol)
Mass XeF₆ = (0.143 mol H₂)(1 mol XeF₆/3 mol H₂)(245.28 g/mol) = <em>11.69 g</em>
Answer:
The rate law may be determined only by experiment.
Explanation:
For a reaction, A + B ---> C, the rate law can only be determined from experimental data. Chemists determine the rate of reaction by carefully observing the changes in the concentration of species as the reaction progresses.
Hence, the rate law is not determined by inspection of the chemical reaction equation, it must be obtained from the experimental data, hence the answer given.
