<span>With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.</span>
Let , side lawn is a.
Area of boundary is :
Now, total cost is given by :
Area left is :
Price to empty space with turfs is :
Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
Answer:
It is c = kt.
Step-by-step explanation:
This is direct variation . As the time increases the number of cranes increases.
The equation is c = kt where k is the constant of variation. In this case it will be a positive value because c is increasing with time.
If they make 20 cranes in 10 minutes then we can find the value of k by plugging in these values;
20 = k * 10
g = 20/10
k = 2.
So they make 2 cranes per minute.
<span>For the question "Mike's closing costs will add up to 4 percent and he'll make a down payment of 20 percent on a house that costs $210,000. Over the life of his loan, he will pay $197,040.76 in monthly payments. What is the total cost of his house?"
To obtain the total cost of the house, we first obtain the amount he paid as the closing costs and the down payment he paid which we will add to the total amount paid in monthly payments.
Closing cost = 4% of $210,000 = 0.04 x 210,000 = $8,400
Down payment = 20% of $210,000 = 0.2 x 210,000 = $42,000
Total monthly payments = $197,040.76
Total cost of the house = $8,400 + $42,000 + $197,040.76 = $247,440.76</span>
Answer:
And if we use the permutation formula given by:
And replacing we got:
Step-by-step explanation:
For this problem we want to find the following expressionÑ
And if we use the permutation formula given by:
And replacing we got:
