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BaLLatris [955]
2 years ago
15

One year ago, Debra purchased 5,400 shares of KNF stock for $218,056. Today, she sold those shares for $19.49 a share. What is t

he capital gains yield on this investment if the dividend yield is 1.7 percent?
A.-28.01 percent
B.-48.28 percent
C.3.07 percent
D.-51.73 percent
E.4.53 percent
Business
1 answer:
kramer2 years ago
7 0

Answer:

Capital gain yield will be -51.73%

So option (d) will be the correct answer

Explanation:

We have given that Debra purchased 4500 shares of KNF stock for $218056

So price of one share =\frac{218056}{5400}=$48.380

So the beginning price = $40.380

She sold the share at price of 19.49 per share

So ending price = $19.49

We have to find the capital gain yield

We know that capital gain yield is given by

Capital gain yield =\frac{end\ price-beginning\ price}{begninning \ price}=\frac{19.49-40.380}{40.390}=-51.73 %

So option (d) will be correct option  

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George Jefferson established a trust fund that will provide $170,500 per year in scholarships. The trust fund earns an annual re
Dimas [21]

Answer:

$8,119,048

Explanation:

Given that,

Amount of scholarships = $170,500 per year

Trust fund earns an annual rate of return = 2.1 percent

Let x be the amount contribute to the fund and assuming that only income is distributed,

2.1% of x = Amount of scholarships

0.021x =  $170,500

x = $170,500 ÷ 0.021

  = $8,119,048

Therefore, the amount of money that is contributed by the George Jefferson to the trust is $8,119,048.

4 0
1 year ago
Pharoah Company just began business and made the following four inventory purchases in June: June 1 186 units $1290 June 10 248
kherson [118]

Answer:

<u>Ending Inventory 2,092</u>

<u></u>

Explanation:

PURCHASES  

DATE QUANTY PRICE         SUBTOTAL

1       186                 $6.935484   $1,290.00

10      248                   $7.78226   $1,930.00

15      248                  $8.38710   $2,080.00

28       186                  $8.81720   $1,640.00

<em>Inventory on hand 260</em>

Using FIFO <u>we have to pick from the bottom of the table</u> until reach 240 unit.

last line: June 28th 186 units total cost 1640

<em>240 - 186 = 54 units </em>

we need 54 more units so we go to next purchase

June 15th 54 units  at 8.3810 = 542.034 = 542

Now we add to get total ending ivnentory

186 units 1640

54 units 452

<u>Ending Inventory 2,092</u>

5 0
2 years ago
Read 2 more answers
Forte Co., had 3,000 units of work in process on April 1 that were 60% complete. During April, 11,000 units were started and as
LUCKY_DIMON [66]

Answer:

a. 10,000 units

Explanation:

The computations of units completed are shown below:

= Beginning work in process units + units started - closing work in process units

= 3,000 units + 11,000 units - 4,000 units

= 10,000 units

For this question, we ignored the equivalent units as the question has asked about the completed units only

So, all other information is irrelevant

6 0
2 years ago
Uan recently completed 20 years of service in the army. during this time, he managed to save a little money and is entitled to a
bixtya [17]
<span>keep it small, especially in the beginning

Small businesses die when you expand too quickly in the beginning</span>
3 0
1 year ago
The united states department of agriculture (usda) found that the proportion of young adults ages 20–39 who regularly skip eatin
Sunny_sXe [5.5K]

Answer:

probability  = 0.3557

Explanation:

given data

young adults ages =  20 to 39

skip eating breakfast p = 0.238

random sample of size n = 500

to find out

we find the probability that the number of individuals in Lance's sample who regularly skip breakfast is greater than 122

solution

we use here Normal Approximation to Binomial Distribution

so first consider random variable = x

so

x~ Bin (n,p)   .............1

and here Normal Approximation will be

x~ Normal Approx (np, npq)    .................2

so it will be

x~ (500, 0.238)  

as here we know q will be

q = 1 - p

q = 1 - 0.238

q = 0.762    .............3

so

here x~ Normal Approx (119, 90.678)

and now we get P(X > 122)

so

We will convert it to Z by as that

z = \frac{x-\mu}{\sigma}     ................4

and here

mean  \mu = np

and standard deviation \sigma =  \sqrt{npq}

so here for P(X > 122)

P(\frac{X-\mu}{\sigma}>\frac{122-119}{\sqrt{90.678}})     ............5

and it is  P(Z>0.37)

so

probability  = 1 - P(Z<0.37)

now we use here z table for value

probability  = 1-0.6443

probability  = 0.3557

7 0
1 year ago
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