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2 years ago

Why would a prism beat a sphere in a competition

Mathematics

2 answers:

Sonja [21]2 years ago

0 0

Answer:

Because a prism has a flat-ish side, but a sphere is only circular. Also a sphere would be harder to control. (I think)

Lostsunrise [7]2 years ago

0 0

Answer:

Bc a prism is pointed and a sphere is rouneded

Step-by-step explanation:

You might be interested in

Zachary’s final project for college course took a semester to write and had 95,234 words.zachary wrote 35,295 words the first mo

kap26 [50]

Answer:

40,999

Step-by-step explanation:

95,234-35,295= 59,939 and then 59,939-19,240= 40,999

5 0

2 years ago

What is the area of the shaded region?

azamat

Answer:

$(25\pi\ -24)\ cm^{2}$

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the circle minus the area of the two isosceles triangles

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

where r is the radius of the circle

In this problem we have

$r=5\ cm$

substitute

$A=\pi (5)^{2}$

$A1=25\pi\ cm^{2}$

Find the area of the two triangles

The area of the two isosceles triangles is equal to

$A=2[\frac{1}{2}bh]=bh$

we have

$b=6\ cm$

$h=5-1=4\ cm$

substitute

$A2=6*4=24\ cm^{2}$

Find the area of the shaded region

$A1-A2=(25\pi\ -24)\ cm^{2}$

5 0

2 years ago

Read 2 more answers

f1(x) = ex, f2(x) = e−x, f3(x) = sinh(x) g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, and c3 so that g(x) = 0 on the int

eimsori [14]

Answer:

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

Step-by-step explanation:

Given

f1(x) = e^x

f2(x) = e^(-x)

f3(x) = sinh(x)

g(x) = 0

We want to solve for C1, C2 and C3, such that

C1f1(x) + C2f2(x) + C3f3(x) = g(x)

That is

C1e^x + C2e^(-x) + C3sinh(x) = 0

The hyperbolic sine of x, sinh(x), can be written in its exponential form as

sinh(x) = (1/2)(e^x + e^(-x))

So, we can rewrite

C1e^x + C2e^(-x) + C3sinh(x) = 0

C1e^x + C2e^(-x) + C3(1/2)(e^x + e^(-x)) = 0

So we have

(C1 + (1/2)C3)e^x + (C2 + (1/2)C3)e^(-x) = 0

We know that

e^x ≠ 0, and e^(-x) ≠ 0

So we must have

(C1 + (1/2)C3) = 0...........................(1)

and

(C2 + (1/2)C3) = 0..........................(2)

From (1)

2C1 + C3 = 0

=> C3 = -2C1.................................(3)

From (2)

2C2 + C3 = 0

=> C3 = -2C2................................(4)

Comparing (3) and (4)

2C1 = 2C2

=> C2 = C1

Let C1 = C2 = K

C3 = -2K

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

3 0

2 years ago

You are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing th

Pachacha [2.7K]

Solving this problem needs the distance formula of point to a line.

The formula is:

distance = | a x + b y + c | / √ (a^2 + b^2)

So we are given the equation: y = 2 x + 4

Rewriting this would be: y – 2 x – 4 = 0 -> a = -2, b = 1, c = -4

We are also given the points:

(-4, 11) = (x, y)

Plugging it in the distance formula at points (x, y):

distance = | -2 * -4 + 1 * 11 + -4 | / √ [(- 2)^2 + (1)^2]

= 15 / √ (5)

= 6.7

So the tree is approximately 6.7 feet away from the zip line.

4 0

2 years ago

Every weekend, jaylon downloads interesting music on his phone from an app. He downloads 15 songs at $1.99 and 7 songs at $2.50.

butalik [34]

Answer:

15*1.99

7*2.50

Step-by-step explanation:

I think you would multiply them (im not sure im not very good with math if its wrong im really sorry hope you get it though good luck :) ! )

6 0

2 years ago