A large cylindrical tank contains 0.750 m3 of nitrogen gas at 27°C and 7.50 * 103 Pa (absolute pressure). The tank has a tight‐f
1 answer:
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Explanation:
The given reaction equation will be as follows.
Now, number of atoms on reactant side are as follows.
- H = 2
- S = 1
- O = 3
Number of atoms on product side are as follows.
- H = 2
- S = 1
- O = 3
Therefore, this equation is balanced since atoms on both reactant and product sides are equal.
Thus, we can conclude that there is one sulfur atom in the products.
<h3>Answer:</h3>
112.08 mL
<h3>Explanation:</h3>From the question we are given;
- Initial volume, V1 = 100.0 mL
- Initial temperature, T1 = 225°C, but K = °C + 273.15
thus, T1 = 498.15 K
- Initial pressure, P1 = 1.80 atm
- Final temperature , T2 = -25°C
= 248.15 K
- Final pressure, P2 = 0.80 atm
We are required to calculate the new volume of the gases;
- According to the combined gas law equation;
Rearranging the formula;
Therefore;
Therefore, the new volume of the gas is 112.08 mL