Answer:
For the sampling distribution,
a) Mean = μₓ = 55.0 students.
b) Standard Deviation = 1.8 students.
Step-by-step explanation:
The complete Question is attached to this solution.
The Central limit theorem explains that for the sampling distribution, the mean is approximately equal to the population mean and the standard deviation of the sampling distribution is related to the population standard deviation through
σₓ = (σ/√n)
where σ = population standard deviation = 4
n = sample size = 5
Mean = population mean
μₓ = μ = 55 students.
Standard deviation
σₓ = (σ/√n) = (4/√5) = 1.789 students = 1.8 students to 1 d.p
Hope this Helps!!!
<span>With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.</span>
The answer is 10/36 or 27.77%
here’s the working out
Answer:
one possible number of bonus is 9.
Step-by-step explanation:
Let, the number of $250 bonus = x and number of $750 bonus = y.
We have that bonuses are given in amounts $250 and $750.
Since, the total bonus is $3000.
So, we get,
250x + 750y = 3000.
As, there is atleast one $250 bonus and atleast one $750 bonus.
Let, the minimum number of bonus of $750 be 1 i.e. y = 1.
Substitute in the equation gives,
250x + 750 × 1 = 3000
i.e. 250x = 3000 - 750
i.e. 250x = 2250
i.e. x = 9
Thus, the maximum number of $250 bonus are 9.
Hence, one possible number of bonus is 9.
Square's side range is (√0,√100) =(0,10); this more than 0 and less than 10.
