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Sphinxa [80]
2 years ago
13

Alice sleeps an average of 9 hours per night a cat can sleep up to 20 hours per day about how many more hours does a cat sleep i

n one month and Alex estimate
Mathematics
1 answer:
SashulF [63]2 years ago
7 0

Answer:

330 hs

Step-by-step explanation:

If Alice sleeps an average of 9 hs and her cat sleeps an average of 20 hours each day we can say that her cat sleeps an average of 11 hours more per day than her.

If the cat sleeps 11 hours more than her per day, for getting the hours he sleeps more by month we just need to multiply the daily value by the number of days in a month. Thus,

30 * (11) = 330

So, her cat sleeps an average of 330 hours more than her in a month, which can be decomposed in 11 hours a day.

I hope it is understandable.

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1 year ago
The ceiling of Katie’s living room is a square that is 10 ft long on each side. Katie knows the diagonal of the ceiling from cor
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Answer: 14 feet. a. The Pythagorean theorem is a^2 + b^2 = c^2, where a and b are the sides of a right angle. By plugging in the sides of the wall, and solving for c, you can find the answer. 10^2 + 10^2 = c^2

| 100 + 100 = c^2 | 200 = c^2 | c = sqrt 200 | c = 14. The other way to solve this would be using the trig functions. You know that the angle between the hypotenuse and the wall side is 45 degrees, so you can use Sine to determine the hypotenuse. Sine is equal to opposite over hypotenuse. Sin (45) = 10/h | Sin (45) * h = 10 | h = 10/Sin (45) | h = 14. Both of the methods result in 14.

Read more on Brainly.com - brainly.com/question/16274528#readmore

Step-by-step explanation:

5 0
1 year ago
Sal was tired of waiting for Amir to show up at their meeting place, so he started running at an average speed of 4.5 mph withou
skelet666 [1.2K]
Let s and a represent the position of Sal and Amir respectively.

s=.75+4.5t  and a=-.25+6.7t

When Sal catches Amir, s=a so we can say.

-.25+6.7t=.75+4.5t  subtract 4.5t from both sides

-.25+2.2t=.75  add .25 to both sides

2.2t=1  divide both sides by 2.2

t=5/11 hours

t≈0.45 hours  (to nearest hundredth of an hour)
3 0
2 years ago
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