Answer:
4.979044478499338 × 10²⁶
Step-by-step explanation:
Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.
Combination factorial is define by ⁿCr = 
21 group of mice receiving Drug A can be selected in ⁶⁰C₂₁ = 
(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug
Drug B 21 mice can be chosen with ³⁹C₂₁ = 
( 39 - 21 = 18) remained for control with ¹⁸C₁₈ = 
The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ = × × = 4.979044478499338 × 10²⁶
We have to find how the chess player can move a knight from one location to another.
Also we have to remember that the bottom - left square is labelled ( 1 , 1 ).
First he wants to move a knight from ( 3 , 2 ) to ( 5 , 1 ).
Answer: 2 squares left, 1 square down.
Then he wants to move it from ( 5 , 1 ) to ( 6 , 3 ).
Answer: 2 squares right, 2 squares up, 1 square left.
Answer:
2.6
Step-by-step explanation:
just put one part of the equation in y1 and the other in y2 and hit 2nd trace 5 an hit enter 4 times
then it will bring a graph hit enter 3 time again and it will show u the answer at the bottom left
Answer:
The probability of not rain during the entire festival is 0.19
Step-by-step explanation:
The Complement Rule states that the sum of the probabilities of an event and its complement must equal 1.
In this case we have the probability of raining of each day, we need the probability of NOT raining.
First day= 45% chance of rain, the complement is 55%
Second day 55% chance of rain, the complement is 45%
Third day a 10% chance of rain, the complement is 90%
Fourth day a 10% chance of rain, the complement is 90%
Fifth day 5% chance of rain, the complement is 95%
To get the probability of NOT raining in the entire festival is the multiplication of all the complements.
P(not raining) = 0.55 x 0.45 x 0.90 x 0.90 x 0.95= 0.19
Area of a rectangle = W X L
Area of a rectangle = 5 X 2
Area of a rectangle = 10
Area of triangle 1= 1/2 X B X H
Area of triangle 1= 1/2 X 2 X 2
Area of triangle 1= 1/2 X 4
Area of triangle 1= 2
Area of triangle 2= 1/2 X B X H
Area of triangle 2= 1/2 X 7 X 4
Area of triangle 2= 1/2 X 28
Area of triangle 2= 14
Area of a rectangle + Area of triangle 1 + Area of triangle 2=
10 + 2 + 14 = 36
