2 years ago

Re Math 7 - Q1 - 13687

Mathematics

1 answer:

NeTakaya2 years ago

4 0

Answer:

i think it might be a or c

Step-by-step explanation:

because 12 =3

You might be interested in

A consumer protection agency is testing a sample of cans of tomato soup from a company. If they find evidence that the average l

EastWind [94]

Answer:

I think it might be a bit I'm not sure

3 0

2 years ago

ABC and AED are straight lines.

grandymaker [24]

Answer:

CD = 5.7 cm
ED = 3.05 cm

Step-by-step explanation:

a) ΔACD ~ ΔABE so the ratios of corresponding sides are the same. That is ...

CD/BE = CA/BA

CD/3.8 = 12.3/8.2

CD = 3.8×12.3/8.2 = 5.7 . . . . cm

b) As above, the ratios of corresponding sides are the same.

ED/AD = BC/AC

ED/9.15 = (12.3-8.2)/12.3 . . . . BC = AC - AB

ED = 9.15×4.1/12.3 = 3.05 . . . . cm

6 0

2 years ago

Radium decays according to the function Q(t) = Q0e-kt where Q represents the quantity remaining after t years and k is the decay

Bingel [31]

Solve

hmmm
half life
well, 120 to 60 is half

60=120e^(-0.00043t)
solve for t
divide both sides by 120
1/2=e^(-0.00043t)
take ln of both sides
ln(1/2)=-0.00043t
divide both sides by -0.00043
ln(1/2)/-0.00043=t
t≈1611.97 years
about 1612 years

3 0

2 years ago

A very weak university is on and off probationary status with the accrediting agency. A different procedure is used in July and

tino4ka555 [31]

Answer:

0.3425 = 34.25% probability it will be off probation in February 2020

Step-by-step explanation:

We have these desired outcomes:

Off probation in July 2019, with 0.25 probability, then continuing off in January, with 1 - 0.08 = 0.92 probability.

Still in probation in July 2019, with 1 - 0.25 = 0.75 probability, then coming off in January, with 0.15 probability.

What is the probability it will be off probation in February 2020?

$p = 0.25*0.92 + 0.75*0.15 = 0.3425$

0.3425 = 34.25% probability it will be off probation in February 2020

6 0

2 years ago

Nyoko needs to be at school at 7:45 AM. It takes her 15 minutes to walk to school, 5/12 hour to eat breakfast, 0.7 hour to get d

defon

So, she wants to be at school at 7.40 (5 mins early)

she needs:

15 mins
5/12 hours (which is $\frac{5}{12} = \frac{25}{60}$ , so 25 mins

so far: 40 mins

then 0.7 and 0.15: we can add those, since they're in decimals: 0.85.

how many minutes is this?

$\frac{85}{100} *60= \frac{85}{10} *6=\frac{85}{5} *3=\frac{13}{1} *3=39$

so 39 mins.

together with the previous 40, it's 79 minutes, which is 1 hour and 19 minutes: so she needs to wake up 1 hour and 19 minutes before 7.40 , which is

6.21!

6 0

2 years ago