<span>-Both box plots show the same interquartile range.
>Interquartile range (IQR) is computed by Q3-Q1.
For Mr. Ishimoto's class, Q3 is 35 and Q1 is 31. 35-31 = 4.
For Ms. Castillo's class, Q3 is 34 and Q1 is 30. 34-30 = 4.
</span><span>-Mr. Ishimoto had the class with the greatest number of students.
>Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.
</span><span>-The smallest class size was 24 students.
>Which was Ms. Castillo's class.</span>
Answer:
The fraction of the area of ACIG represented by the shaped region is 7/18
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the square ABED find the length side of the square
we know that
AB=BE=ED=AD
The area of s square is

where b is the length side of the square
we have

substitute


therefore

step 2
Find the area of ACIG
The area of rectangle ACIG is equal to

substitute the given values

step 3
Find the area of shaded rectangle DEHG
The area of rectangle DEHG is equal to

we have 

substitute
step 4
Find the area of shaded rectangle BCFE
The area of rectangle BCFE is equal to

we have


substitute

step 5
sum the shaded areas

step 6
Divide the area of of the shaded region by the area of ACIG

Simplify
Divide by 5 both numerator and denominator

therefore
The fraction of the area of ACIG represented by the shaped region is 7/18
168/3 = 56
<em>Therefore, Chad is driving the car in 56 mph.</em>
672/56 = 12
<em>Therefore, Chad drives 672 miles in 12 hours.</em>
308/11 = 28
<em>Therefore, Chad drives 28 miles per gallon of gas.</em>
672/28 = 24
<em>Therefore, Chad uses 24 gallons of gas to drive 672 miles.</em>
Correct question:
Which reaction describes a beta emission? 2659Fe→ 2759Co + −10e, 88226Ra→ 86222Rn + 24He, 94239Pu + 24He→ 96242Cm + 01n, 54118Xe→ 53118I + +10e
Answer:
2659Fe→ 2759Co + 1e
Step-by-step explanation:
General equation for beta decay is given as;

where;
A is the atomic mass of the element
z is atomic number of the element
X is the parent atom
Y is the daughter element
β is beta emission
In beta emission, there is loss of one electron and zero proton, the will cause the daughter element to gain on electron in order to balance the reaction.
Based on beta decay equation above, we select the reaction that describes beta emission.
2659Fe→ 2759Co + 1e
Here;
A = 59
z = 26
z + 1 = 27