Answer:
- def is_prime(n):
- for i in range(2, n):
- if(n % i == 0):
- return False
- return True
-
- prime_truths = [is_prime(x) for x in range(2,101)]
- print(prime_truths)
Explanation:
The solution code is written in Python 3.
Presume there is a given function is_prime (Line 1 - 5) which will return True if the n is a prime number and return False if n is not prime.
Next, we can use the list comprehension to generate a list of True and False based on the prime status (Line 7). To do so, we use is_prime function as the expression in the comprehension list and use for loop to traverse through the number from 2 to 100. The every loop, one value x will be passed to is_prime and the function will return either true or false and add the result to prime_truth list.
After completion of loop within the comprehension list, we can print the generated prime_truths list (Line 8).
Answer:
It will be a java code.
Explanation:
import java.util.Scanner;
public class StringInputStream {
public static void main (String [] args) {
Scanner inSS = null;
String userInput = "Jan 12 1992";
inSS = new Scanner(userInput);`
String userMonth = "";
int userDate = 0;
int userYear = 0;
/* Your solution goes here */
System.out.println("Month: " + userMonth);
System.out.println("Date: " + userDate);
System.out.println("Year: " + userYear);
return;
}
}
Answer:
See explaination for the program code
Explanation:
code:
public static int[] countLastDigits(int[] list) {
int[] count = new int[10];
for (int i = 0; i < list.length; i++) {
int digit = list[i] % 10;
count[digit]++;
}
return count;
}
Solution :
class Employee:
#Define the
#constructor.
def __
__(
, ID_number, 
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict
The Contact Details of the DTP firm would usually be found at the bottom of the flyer, to give way to the event to be advertised on the top and the middle of the flyer.
