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Yakvenalex [24]
2 years ago
11

A circular loop of wire lies flat on a level table top in a region where the magnetic field vector points straight upward. the m

agnetic field suddenly vanishes. as viewed from above, in what direction does the induced current flow in the loop of wire?
Physics
1 answer:
mr_godi [17]2 years ago
7 0
The magnetic field direction and direction of induced current in a wire are related by the right hand grip rule. Since the magnetic field was upwards, the thumb points upwards and the fingers curl around it. When viewed from above, it is seen as a current flowing in the counter clockwise direction.
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A metal bar moves through a magnetic field. the induced charges on the bar are
Dmitry [639]
I would say its a positive cgarge
7 0
2 years ago
Seven seconds after a brilliant flash of lightning, thunder shakes the house. approximately how far was the lightning strike fro
tangare [24]
Very roughly 7,700 feet ... about 1.5 miles.
8 0
2 years ago
Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer
kodGreya [7K]

The peak wavelength of Betelgeuse is 828 nm

Explanation:

The relationship between surface temperature and peak wavelength of a star is given by Wien's displacement law:

\lambda=\frac{b}{T}

where

\lambda is the peak wavelength

T is the surface temperature

b=2.898\cdot 10^{-3} m\cdot K is Wien's constant

For Betelgeuse, the surface temperature is approximately

T = 3500 K

Therefore, its peak wavelength is:

\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm

Learn more about wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

8 0
2 years ago
1. Si tengo medio kilo de fruta y te doy un cuarto y tú me das tres cuartos de kilo, ¿cuánto tengo? 2. Si en una carrera te qued
Kipish [7]

Answer:

1. Tienes 1 kg de fruta.

2. Queda por recorrer 1/4 km.

3. Ambos pesan lo mismo.

Explanation:

1. Tienes 1/2 kg y cuando te doy 1/4 te queda:

m = \frac{1}{2} - \frac{1}{4} = \frac{1}{4}

Ahora cuando te doy 3/4 kg te queda en total:

m_{T} = \frac{1}{4} + \frac{3}{4} = 1 kg

Por lo tanto, tienes 1 kg de fruta al final.

2. Si falta por recorrer la mitad de la mitad, tenemos:

d = \frac{1/2}{2} = \frac{1}{4}

Entonces, queda por recorrer 1/4 km.

3. El peso (P) del hierro es:

P = m*g    

P = (1 + 1/2)kg*9.81 m/s^{2} = 14.72 N

Y el peso de la paja es:

P = 3/2 kg*9.81 m/s^{2} = 14.72 N

Por lo tanto, ambos pesan lo mismo.

Espero que te sea de utilidad!

6 0
2 years ago
A radioactive source has a half life of 80s.
Burka [1]
Lets make the original number of nuclides at the start is 100.

If 7/8 of 100 is decayed, that means 87.5 decayed.

\frac{7}{8} \times 100 = 87.5

And there is 1/8 left of the number of nuclide 100. Which is 12.5

100 - 87.5 =12.5

\frac{1}{8} \times 100 = 12.5

How many Half lifes passed for 100 to become 12.5 is 3 Half-Lives.

100 \div 2 \div 2 \div 2 = 12.5

Each Half-Life is 80 seconds so there is 240 seconds

3 \times 80 = 240The answer is that it takes 240 seconds.
6 0
2 years ago
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