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natta225 [31]
2 years ago
3

An often-overlooked consequence of power generation is "thermal pollution" from excess heat deposited in the envi- ronment. The

heating can be considerable. Here are some typical numbers: A nuclear power plant generates 1.0 GW of electric power with an operating efficiency of 35%. The reactor has a single-pass cooling system; water from a nearby river is brought in, warmed, and returned to the river. When operating at full power, the plant takes in 90 m3 of water second, comparable to the flow of a small river. If the river water comes in at 10°C, at what temperature does it emerge?
Physics
1 answer:
weeeeeb [17]2 years ago
8 0

Answer:

Explanation:

1 GW = 10⁹ W

35% of 10⁹ W

= 35 x 10⁷W

Q =  35 x 10⁷J

Mass of water

= volume x density

= 90 x 10³ kg

= 9 x 10⁴ kg

specific heat s = 4.142 x 10³ J / kg

Now

Q = ms Δ T

Δ T is rise in temp

Δ T = Q / ms

= 35 x 10⁷ / (9 x 10⁴ x4.142 x 10³)

= .94°C

So the emerging water will have temperature of

10.94 °C.

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The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of 58.0° above the horizo
Norma-Jean [14]

Answer:

0.528m

Explanation:

a)58.7 cm = 0.587 m

Let g = 9.8m/s2. When the frog jumps from ground to the highest point its kinetic energy is converted to potential energy:

E_p = E_k

mgh = mv^2/2

where m is the frog mass and h is the vertical distance traveled, v is the frog velocity at take-off

v^2 = 2gh = 2*9.8*0.587 = 11.5

v = \sqrt{11.5} = 3.4 m/s

b) Vertical and horizontal components of the velocity are

v_v = vsin(\alpha) = 3.4sin(58^0) = 2.877 m/s

v_h = vcos(\alpha) = 3.4cos(58^0) = 1.8 m/s

The time it takes for the vertical speed to reach 0 (highest point) under gravitational acceleration g = -9.8m/s2 is

\Delta t = \Delta v / g = \frac{0 - 2.877}{-9.8} = 0.293s

This is also the time it takes to travel horizontally, we can multiply this with the horizontal speed to get the horizontal distance it travels

s_h = v_ht = 1.8*0.293 = 0.528 m

3 0
2 years ago
A wedge with an inclination of angle θ rests next to a wall. A block of mass m is sliding down the plane. There is no friction b
Softa [21]

Answer:

  The net force on the block  F(net)  = mgsinθ).

   Fw =mg(cosθ)(sinθ)

Explanation:

(a)

Here, m is the mass of the block, n is the normal force, \thetaθ is the wedge angle, and Fw  is the force exerted by the wall on the wedge.

Since the block sliding down, the net force on the block is along the plane of the wedge that is equal to horizontal component of weight of the block.

                    F(net)  = mgsinθ

The net force on the block  F(net)  = mgsinθ).

The direction of motion of the block is along the direction of net force acting on the block. Since there is no frictional force between the wedge and block, the only force acting on the block along the direction of motion is mgsinθ.

(b)

From the free body diagram, the normal force n is equal to mgcosθ .

                           n=mgcosθ

The horizontal component of normal force on the block is equal to force

                           Fw=n*sin(θ) that exerted by the wall on the wedge.

Substitute mgcosθ for n in the above equation;

                           Fw =mg(cosθ)(sinθ)

Since, there is no friction between the wedge and the wall, there is component force acting on the wall to restrict the motion of the wedge on the surface and that force is arises from the horizontal component for normal force on the block.

6 0
2 years ago
An object of mass 8.0 kg is attached to an ideal massless spring and allowed to hang in the Earth's gravitational field. The spr
neonofarm [45]

Answer:

2.63 Hz

Explanation:

m = mass of the object = 8.0 kg

x = stretch in the spring = 3.6 cm = 0.036 m

k = spring constant of the spring

using equilibrium of force

Spring force = weight of object

k x = m g

k (0.036) = (8) (9.8)

k = 2177.78 N/m

frequency of oscillation is given as

f = \frac{1}{2\pi }\sqrt{\frac{k}{m}}

f = \frac{1}{2\pi }\sqrt{\frac{2177.78}{8}}

f =  2.63 Hz

4 0
2 years ago
Read 2 more answers
Bill drives and sees a red light. He slows down to a stop. A graph of his velocity over time is shown below.
antoniya [11.8K]

Answer:

-2 m/s^2

Explanation:

Acceleration is equal to the slope of the graph. You just find the slope of that section. The rise is -20 and the run is 10, so you get -2.

5 0
2 years ago
Read 2 more answers
A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare
arsen [322]

First thing plot a right angle with angle of elevation of 35degrees as shown in figure then use SOHCAHTOA.

Ay/Helicopter = sin 35

Ay = 86 sin 35 = 36.8237

Ax/Helicopter = cos 35

Ax = 86 cos 35 = 77.7175

Note: I ignore the negative signs coz they signify direction



4 0
2 years ago
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