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Ann [662]
2 years ago
12

At what angle (relative to the horizontal) should a curve 52 m in radius be banked if no friction is required to prevent the car

from slipping when traveling at 12 m/s? (g = 9.8 m/s^2 )
Physics
1 answer:
velikii [3]2 years ago
7 0

Answer:

Banking angle, \theta=15.77^{\circ}

Explanation:

It is given that,

Radius of the curve, r = 52 m

Speed of the car, v = 12 m/s

Acceleration due to gravity, g=9.8\ m/s^2

Let the curved is banked at an angle of \theta with respect to the horizontal. It is given by :

tan\theta=\dfrac{v^2}{rg}

tan\theta=\dfrac{(12)^2}{52\times 9.8}                

\theta=15.77^{\circ}

So, the curve is banked at an angle of 15.77 degrees wrt the horizontal. Hence, this is the required solution.

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A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00
mote1985 [20]

Answer:

1. 6.99x 10^-6V/m

2. 18m

Explanation:

See attached file

7 0
2 years ago
You are asked to design a spring that will give a 1160-kg satellite a speed of 2.50 m>s relative to an orbiting space shuttle
Tju [1.3M]
Given:
m = 1160 kg
g = 9,81 m/s²
v = 2.5 m/s

Unknown:
k spring constant
x spring compression

1. equation to use is Newton's 2nd law and Hook's law:
F = ma = m(5g) = |kx|
2. equation to use, the energy of the spring must equal the energy of the satellite:
\frac{1}{2} kx^2 = \frac{1}{2} mv^2
 Combinig the two equations:
\frac{1}{2} mv^2 =  \frac{1}{2}  m(5g)x \\ v^2 = 5gx \\ x =  \frac{v^2}{5g}  \\  \\ k =  \frac{m(5g)}{x} =  \frac{m(5g)^2}{v^2}

7 0
2 years ago
A particle is in uniform circular motion. Assume a standard rtz coordinate system. If you deconstruct the net force acting on th
Kitty [74]

Answer:

a) One

Explanation:

In a uniform circular motion there must be a force acting to keep it in the circular track. This force can either be centripetal or a centrifugal force.

According to the Newton's first law of motion a particle continues to be in state of rest or in uniform motion until acted upon by an external force.

Here the term uniform motion need to be understood which refers to the uniform velocity of the particle in accordance to the vector laws.

3 0
2 years ago
Use the formula a=h/n to find the batting average a of a batter who has h hits in n times at bat. Solve the formula for h. if a
Inessa [10]
A = h / n => h = a*n

a = 0.290 hit / time
n = 300 times

=> h = 0.290 hit / time * 300 time = 87 hits

Answer: 87 hits
4 0
2 years ago
A 2.0-m-tall man is 5.0 m from the converging lens of a camera. His image appears on a detector that is 50 mm behind the lens. H
ladessa [460]

Answer:

20 cm

Explanation:

We can solve the problem by using the magnification equation:

M=\frac{h_i}{h_o}=-\frac{q}{p}

where

h_i is the size of the image

h_o = 2.0 m is the height of the real object (the man)

q=50 mm =0.050 m is the distance of the image from the lens

p = 5.0 m is the distance of the object (the man) from the lens

Solving the formula for h_i, we find

h_i = -\frac{q}{p}h_o=-\frac{0.050 m}{5.0 m}(2.0 m)=-0.02 m = -20 cm

And the negative sign means the image is inverted.

6 0
2 years ago
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