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Readme [11.4K]
2 years ago
8

If the input water is labeled with a radioactive isotope of oxygen, 18O, then the oxygen gas released as the reaction proceeds i

s also labeled with 18O. Which of the following is the most likely explanation (A) During the light reactions of photosynthesis, water is split, the
hydrogen atoms combine with the CO2, and oxygen gas is released.
(B) During the light reactions of photosynthesis, water is split, removing
electrons and protons, and oxygen gas is released.
(C) During the Calvin cycle, water is split, regenerating NADPH from
NADP+, and oxygen gas is released.
(D) During the Calvin cycle, water is split, the hydrogen atoms are added
to intermediates of sugar synthesis, and oxygen gas is released.
Chemistry
2 answers:
tensa zangetsu [6.8K]2 years ago
7 0

Answer:

A

Explanation:

During the light stage of photosynthesis, water splits in a photolysis reaction. The hydrogen now combines with CO2 to form the sugar and the oxygen originally from the water is released back into the atmosphere.

Lelu [443]2 years ago
5 0

Answer:

b. During the light reactions of photosynthesis, water is split, removing electrons and hydrogen ions, and oxygen gas is released.

Explanation:

During the light reactions of photosynthesis the oxygen present in the water is released.

As we know, photosynthesis happens when chlorophyll absorbs sunlight. At that time, the water and carbon dioxide captured by the plant are converted into a glucose molecule. During this process, the water is "broken", losing electrons and hydrogen ions. In this case, the oxygen ends up being thrown out of the reaction and dissolved in the environment. You can observe this process through the equation below:

6 CO2 + 12 H2O ----> C6H12O6 + 6 O2 + 6 H2O

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According to Newton's first law of physics, what will a bowling ball do as it rolls down the bowling alley?
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Answer:

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Explanation:

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Are the strengths of the interactions between the particles in the solute and between the particles in the solvent before the so
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Answer:

Less than

Explanation:

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5 0
2 years ago
Be sure to answer all parts. calculate δg o for the reaction between i2(s) and br−(aq). e o cell = −0.54 j/c enter your answer i
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Answer:

See explaination

Explanation:

See attachment for the detailed step by step solution of the given problem.

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3 0
2 years ago
A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0.150 M AuNO 3 solution at 25 °C. The gold wire i
almond37 [142]

The half reaction that occurs at the Au electrode is  1.64

<u>Explanation:</u>

Half cell reaction at 'Au' electrode

We have the equation,

Au + (aq) + e-  ---> Au(s)

Given the concenration of AuNO3=0.150 M

[Au +] =0.150 m

From the equation,

Au + (aq) + e-  ---> Au(s)

Standard electric potential= Eo= 1.69 volt

Solving the problem using the Nerst equation

E cell= E0 cell - 2.303 RT/ nF  log Qc

Where,

T = 298 K

n= no of electron lost or gained

F= faraday's constant= 965000/mole

R= universal constant= 8.314 J/ K/ Mole

Substitue the values we get

E cell = 1.69 volt - 0.05 g/n log (1/0.150M)

E cell = 1.69 volt - 0.05 g/1  0.824

E cell= 1.64

The half reaction that occurs at the Au electrode is  1.64

<u />

6 0
2 years ago
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