Answer:
B) a helium nucleus moving at a velocity of 1000 mph
Explanation:
According to the De Broglie relation
λ= h/mv
h= planks constant
m= mass of the body
v= velocity of the body.
As we can see from De Broglie's relation, the wavelength of matter waves depends on its mass and velocity. Hence, a very small mass moving at a very high velocity will have the greatest De Broglie wavelength.
Of all the options given, helium is the smallest matter. A velocity of 1000mph is quite high hence it will have the greatest De Broglie wavelength.
Answer:
6.696 g/cm3
Explanation:
From the question;
Mass = 17.41g
Volume of water before = 46.3 cm3
Volume of water after = 48.9 cm3
Volume of antimony = Volume after - Volume before = 48.9 - 46.3 = 2.6 cm3
Density = Mass / Volume
Density = 17.41 / 2.6 = 6.696 g/cm3
Answer:
It is a crystalline solid.
It is a white crystalline solid that is practically insoluble in water, soluble in diethyl ether and slightly soluble in ethanol
Explanation:
The difference between crystalline and amorphous is how this chemical compound transmits light.
When a chemical material or compound is said to be crystalline, it is the opposite of what we imagine, since its color is opaque and does not allow light to pass through it, that is why this compound, being crystalline, is opaque white. and if you want to see through it you will not see the other way since it is not "transparent".
On the other hand, amorphous chemical materials or compounds are seen through them from one side to the other, they are considered "transparent" and do not refract any color from the color range of light. That is why they are not opaque either, nor do they have a particular color like white. A clear example of an amorphous structure is glass or crystal.
We use the formula:
PV = nRT
First let us get the volume V:
volume = 14 ft * 12 ft * 10 ft = 1,680 ft^3
Convert this to m^3:
volume = 1680 ft^3 * (1 m / 3.28 ft)^3 = 47.61 m^3
n = PV / RT
n = (1 atm) (47.61 m^3) / (293.15 K * 8.21x10^-5 m3 atm /
mol K)
<span>n = 1,978.13 mol</span>
Answer:
0.12693 mg/L
Explanation:
First we <u>calculate the concentration of compound X in the standard prior to dilution</u>:
- 10.751 mg / 100 mL = 0.10751 mg/mL
Then we <u>calculate the concentration of compound X in the standard after dilution</u>:
- 0.10751 mg/mL * 5 mL / 25 mL = 0.021502 mg/L
Now we calculate the<u> concentration of compound X in the sample</u>, using the <em>known concentration of standard and the given areas</em>:
- 2582 * 0.021502 mg/L ÷ 4374 = 0.012693 mg/L
Finally we <u>calculate the concentration of X in the sample prior to dilution</u>:
- 0.012693 mg/L * 50 mL / 5 mL = 0.12693 mg/L
