Answer:
The equation for the rate of this reaction is R = [NO] + {O2}
Explanation:
The rate-determining step of a reaction is the slowest step of a chemical reaction which determines the rate (speed) at which the overall reaction would take place.
Reaction mechanism:
The slow and fast reactions both have NO3 which is cancelled out on both sides, in order to get the overall reaction.
The rate law for this reaction would be that for the rate determining step:
R = [NO] + {O2}
<u>Answer:</u> The chemical reaction is given below.
<u>Explanation:</u>
A fuel cell is defined as the electrochemical cell which converts the chemical energy of a fuel (often used hydrogen) and an oxidizing agent (often used oxygen) into electrical energy via a pair of redox reactions.
The reactions which occur in hydrogen-oxygen fuel cell are:
At cathode: 
At anode: 
Net reaction: 
Thus, the chemical reaction is given above.
Answer:
The dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :
![R=k[C_4H_6]^2](https://tex.z-dn.net/?f=R%3Dk%5BC_4H_6%5D%5E2)
Explanation:

The rate of the reaction ;
![R=k[C_4H_6]^x](https://tex.z-dn.net/?f=R%3Dk%5BC_4H_6%5D%5Ex)
As given in the question , that graph of time verses
was linear but plots of
or
was curved.
Generally:
Graph of time verses
for zero order reaction is linear with negative slope.
Graph of time verses
for secon order reaction is linear with negative slope.
Graph of time verses
for secon order reaction is linear with positive slope.
So, the dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :
![R=k[C_4H_6]^2](https://tex.z-dn.net/?f=R%3Dk%5BC_4H_6%5D%5E2)
Answer: 
Explanation:
First we have to calculate the heat absorbed by bomb calorimeter
Formula used :

= heat absorbed by calorimeter = ?
= specific heat of = 10.69 kJ/K
= final temperature = 
= initial temperature = 

As heat absorbed by calorimeter is equal to the heat released by acetylene during combustion.
Thus 1.53 gram of acetylene releases heat of combustion = 258.7kJ
So, 26.04 g/mole of acetylene releases heat of combustion 
Therefore, the heat of combustion of acetylene is, 