Question

A gas of 3.4 moles occupies a volume of 0.046 L at 298 K. What is the pressure in kPa?

Answer 1

Answer : The correct option is, $2.1\times 10^5kPa$

Explanation :

To calculate the pressure of gas we are using ideal gas equation as:

$PV=nRT$

where,

P = pressure of gas = ?

V = volume of gas = 0.046 L

n = number of moles of gas = 3.4

R = gas constant = 8.314 L.kPa/mol.K

T = temperature of gas = 298 K

Now put all the given values in the above formula, we get:

$P\times (0.046L)=(3.4mol)\times (8.314L.kPa/mol.K)\times (298K)$

$P=1.83\times 10^5kPa\approx 2.1\times 10^5kPa$

Therefore, the pressure of gas is, $2.1\times 10^5kPa$