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cestrela7 [59]
2 years ago
12

From this list, choose all of the ionic compounds. Check all that apply. View Available Hint(s) Check all that apply. POCl3 KOCH

2CH3 CH3OH SOCl2 CH3CH2CO2Na NaOH CH2
Chemistry
1 answer:
Alik [6]2 years ago
4 0

Answer: KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Explanation:

It is known that ionic compounds are the compounds in which one atom transfer its valence electrons to another atom. Hence, during this transfer partial opposite charges tend to develop on the combing atoms due to which strong force of attraction exists between the atoms.

An ionic bond is always formed between a metal and a non-metal.

For example, KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

On the other hand, a compound formed due to sharing of electrons between the combining atoms is known as a covalent compound. Generally, a non-metal with same or different non-metal tends to form a covalent bond.

For example, POCl_{3}, SOCl_{2} etc are all covalent compounds.

Thus, we can conclude that KOCH_2CH_3, [tex]CH_3CH_2COONa, NaOH are all ionic compounds.

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28.4 degrees fahrenheit
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What is the molar mass of al (clo2)3
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A student performed an analysis of a sample for its calcium content and obtained the following results:
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14.9075 g, 28.67%, 0.11%

Explanation:

The mean concentration of calcium = summation x / frequency

= ( 14.92 + 1491 + 14.88 + 14.92 ) /4 = 14.9075 g

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c) relative standard deviation = standard deviation / mean × 100 = 0.0164 /  14.9075 × 100 = 0.11%

d) The accuracy of the measure is the measurement compared to the actual which according to the standard set by the instructor (5%error) is not very accurate because the percent error is high (28.67%) while the relative standard deviation is quite low ( 0.11%) which means the measurement precision is very high.

The student will have to redo the experiment because the experiment was not too accurate since the percent error is way higher than the set value (5%) although the precision was high.

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How many grams are there in 7.5 X10^23 molecules of H2SO4?
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2.3*10^-4 moles contain  2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.

If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.

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