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valkas [14]
2 years ago
4

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

oints A and D belong to the x−axis and m∠BAD=60°

Mathematics
2 answers:
Gnesinka [82]2 years ago
8 0

Answer:

The value of a = ±(√3)/(6)

Step-by-step explanation:

Points A and D belong to the x−axis.

All vertices on the parabola y = a (x+1)(x−5) = a (x² - 4x - 5)

So, points A and D represents the x-intercept of the parabola y

To find x-intercept, put y = 0

∴ a (x+1)(x−5) = 0  ⇒ divide both sides by a

∴ (x+1)(x−5) = 0 ⇒ x = -1 or x = 5

so, the x-coordinate of Point A is -1 or 5

And given that: m∠BAD=60°

So, the tangential line of the parabola at point A has a slope of 60°

∴ y' = tan 60° = √3

∴ y' = a (2x-4)

∴ a (2x-4) = √3

∴ a = (√3)/(2x-4)

Substitute with x = -1 ⇒ a = (√3)/(-6)

Substitute with x = 5 ⇒ a = (√3)/(6)

So, The value of a = ±(√3)/(6)

Also, see the attached figure, it represents the problem in case of a = (√3)/(-6)

solong [7]2 years ago
3 0

Answer:

Step-by-step explanation:

a=+(3+9\sqrt{3})/52\\ a=-(3+9\sqrt{3})/52\\

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Your utility company charges 11 cents per​ kilowatt-hour of electricity. Complete parts​ (a) and​ (b) below. a. What is the dail
Colt1911 [192]

Answer:

a. 9.9 cents

b. 26.5 dollars

Step-by-step explanation:

The first thing they mention to us is the cost of energy 11 cents / kwh

a) In the first point they ask us to calculate the daily cost of keeping the flashlight on for 12 hours, they tell us that it consumes 75 watts per hour, but this value must be passed to kW because the cost is given in kWh

to pass it, it would be: 75 watt * 1 kw / 1000 watt = 0.075 kw,

the formula to apply would be like this:

Daily cost = flashlight cost * time * energy cost

we all know them so we replace:

Daily cost = 0.075 kw * 12 h * 11 cents / kwh = 9.9 cents

b) Now, to know the annual savings, we must calculate the difference between the expense of the normal flashlight and the LED, let's calculate the daily cost of the LED, like this:

20 watt * 1 kw / 1000 watt = 0.02 kw

Daily cost = 0.02 kw * 12 h * 11 cents / kwh = 2.64 cents

Now by calculating the difference we multiply by 365 which are the days of a year.

Savings / year = (9.9 - 2.64) * 365 = 2649.9 cents = 26.5 dollars.

5 0
2 years ago
Cheese costs $4.40 per pound. Find the cost per kilogram. (1kg = 2.2lb)
MakcuM [25]

Answer:

The cost is $9.70 per kilogram.

Step-by-step explanation:

This can be solved by a rule of three.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.

Solution:

The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:

1 pound - xkg

2.2 pound - 1 kg

2.2x = 1

x = \frac{1}{2.2}

x = 0.45kg

Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?

$4.40 - 0.45kg

$x - 1kg

0.45x = 4.40

x = \frac{4.40}{0.45}

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6 0
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allsm [11]

65-9=56

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