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m_a_m_a [10]
2 years ago
14

Which change occurs when a barium atom loses two electrons?(1) It becomes a negative ion and its radius decreases.(2) It becomes

a negative ion and its radius increases.(3) It becomes a positive ion and its radius decreases.(4) It becomes a positive ion and its radius increases.
Chemistry
2 answers:
OleMash [197]2 years ago
6 0

Answer:

The correct answer is option 3, It becomes a positive ion and its radius decreases

Explanation:

As per the Octet rule, Barium has 2 electrons in its outermost shell. When it loses the two electron it gains two positive charge i.e Ba2+. As the barium loses the two electron from its outermost shell, the outermost shell becomes vacant and thus is no more considered as a part of atomic geometry of the barium atom and since the outermost shell is considered negligible the radius of barium atom reduces automatically.  

Tcecarenko [31]2 years ago
5 0
<h2>Changes Occurs when a Barium Atom - Option 3  </h2>

When a barium atom loses two electrons it becomes a positive ion and its radius decreases. Barium (Ba) has atomic number 56 so it has 2 electrons in first shell of an atom to become stable according to duplet rule. Then other 52 electrons revolve in the shells according to octet rules.

Another 2 electrons are in the outermost shell. To become stable electrons lose to form barium ions (Ba+2). Hence, by losing 2 electrons the outermost shell will be diminished so its radius decreases and by losing electrons it becomes positive ions.

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For the reaction PCl5(g) &lt;--&gt; PCl3(g) Cl2(g) at equilibrium, which statement correctly describes the effects of increasing
xenn [34]

The given question is incomplete. The complete question is :

For the reaction PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g) at equilibrium, which statement correctly describes the effects of increasing pressure and adding PCl_5, respectively

a) Increasing pressure causes shift to reactants, adding PCl_5 causes shift to products.

b) Increasing pressure causes shift to products ,adding PCl_5 causes shift to reactants.

c) Increasing pressure causes shift to products, adding PCl_5 causes shift to products.

d) Increasing pressure causes shift to reactants,adding PCl_5 causes shift to reactants

Answer: Increasing pressure causes shift to reactants, adding PCl_5 causes shift to products.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

a)  If the pressure is increased, the volume will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. As the number of moles of gas molecules is lesser at the reactant side. So, the equilibrium will shift in the left direction. i.e. towards reactants.

b) If PCl_5 is added, the equilibrium will shift in the direction where PCl_5 is decreasing. So, the equilibrium will shift in the right direction. i.e. towards products.

8 0
2 years ago
Joelle is a manager at a construction company, and she is interested in the chemistry behind the materials they use. She has beg
vesna_86 [32]

Answer:

The correct answer is - C27H36N2O10.

Explanation:

C27H36N2O10 is the chemical formula of polyurethane foam which is a linear polymer manufactured by reacting polyols and diisocyanates​. Polyurethane foam is used as a thermal insulator.

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5 0
2 years ago
Read 2 more answers
How to correctly solve this problem : 4.05Kg+567.95g+100.1g correct and best way
VARVARA [1.3K]
Check attached file for the answer.

7 0
2 years ago
A gas occupies 22.4 l at stp and 14.5 l at 100c and 2.00 atm pressure. how many moles of gas did the system gain or lose?
azamat
<span>At standard temperature and pressure 22.4 l of an ideal gas would contain 1 mole. in order to find the change in moles we must look at the ideal gas law PV=nRT where P=Pressure V=volume n=Moles R= Gas constant T= Temperature. To simplify this equation we will be using the gas constant at .08206 L-atm/mol-K. We must first convert 100c to k which is 373.15. Then we can plug the values into our equation which gives us (2atm)(14.5 l)=(n)(.08206 L-atm/mol-K)(373.15). After some basic algebra we get the moles to equal roughly .95 which is .05 moles less than our original system.</span>
6 0
2 years ago
Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the sam
mafiozo [28]

Question:

Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the same as pure water at 20.0 degrees C (18 torr). The volume of the mixture is 1.7 L and its total pressure is 0.987 atm. Determine the number of moles of hydrogen gas present in the sample.

A. 0.272 mol

B. 0.04 mol

C. 0.997 mol

D. 0.139 mol

E. 0.0681 mol

Answer:

The correct option is;

E. 0.0681 mol

Explanation:

The equation for the reaction is

Zn + HCl = H₂ + ZnCl₂

Vapor pressure of the liquid = 18 torr = 2399.803 Pa

Total pressure of gas mixture H₂ + liquid vapor = 0.987 atm  

= 100007.775 Pa

Therefore, by Avogadro's law, pressure of the hydrogen gas is given by the following equation

Pressure of H₂ = 100007.775 Pa - 2399.803 Pa = 97607.972 Pa

Volume of H₂ = 1.7 L = 0.0017 m³

Temperature = 20 °C = 293.15 K

Therefore,

n = \frac{PV}{RT} =  \frac{100007.775 \times 0.0017 }{8.3145 \times 293.15} = 0.068078 \ moles

Therefore, the number of moles of hydrogen gas present in the sample is n ≈ 0.0681 moles.

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2 years ago
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