Question

How many grams of O2 are produced from 356.6g of Al2O3

Answer 1

Answer:

168 grams of O2 are produced from 356.6g of Al2O3

Explanation:

Calculate the moles of Al2O3

Given mass = 356.6

Molar mass of Al2O3 = 2(mass of Al) +3(mass of O)

= 2(27) + 3(16)

=102 g/mol

$mole =\frac{given\ mass}{ Molar\ mass}$

$mole =\frac{356.6}{102}$

= 3.5 mole

The balanced equation for the equation is :

$4Al+3O_{2}\rightarrow 2Al_{2}O_{3}$

2 mole of  Al2O3 will give 3 mole of Oxygen

1 mole of  Al2O3 = 3/2 = 1.5 mole of Oxygen

3.5 mole of  Al2O3 = (1.5 x 3.5 ) mole of Oxygen

3.5 mole of  Al2O3  = 5.25 moles of oxygen

Use,

$given\ mass= Molar\ mass\times moles$

Molar mass of O2 = 16(2) = 32 g/mol

$given\ mass= 32\times 5.25$

= 168 g