An animal park has lions, tigers and zebras. 20% of the animals are lions and half of the animals are zebras. If there are 120 a
1 answer:
Answer:
Step-by-step explanation:
Let
x ----> the number of lions
y ----> the number f tigers
z ----> the number of zebras
we know that
----> equation A
Remember that
To find out the number of lions, multiply the total animals by the percentage of lions
To find out the number of zebras, multiply the total animals by the percentage of zebras
Substitute the value of x and the value of z in equation A and solve for y
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Answer:
1
2
3
Step-by-step explanation:
Generally when two fair 6-sided dice is rolled the doubles are
(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)
The total outcome of doubles is N = 6
The total outcome of the rolling the two fair 6-sided dice is
n = 36
Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as
Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is
(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)
Looking at this outcome we see that there are two doubles present
So
The conditional probability that doubles were rolled is mathematically represented as
Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30
And the number of outcomes that at least one die is a 1 is W = 10
So
The conditional probability that at least one die is a 1 is mathematically represented as
=>
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