If the splash is heard 1.17 seconds later, what was the initial speed of the rock? Take the speed of sound in the air to be 343
2 answers:
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49d
<h3>Further explanation</h3>This case is about uniformly accelerated motion.
<u>Given:</u>
The initial speed was v takes distance d to stop after the brakes are applied.
<u>Question:</u>
What is the stopping distance if the car is initially traveling at speed 7.0v?
Assume that the acceleration due to the braking is the same in both cases. Express your answer using two significant figures.
<u>The Process:</u>
The list of variables to be considered is as follows.
The formula we follow for this problem are as follows:
- a = acceleration (in m/s²)
- u = initial velocity
- v = final velocity
- d = distance travelled
Step-1
We substitute v as the initial speed, distance of d, and zero for final speed into the formula.
Both sides are divided by -2d, we get
Step-2
We substitute 7.0v as the initial speed, zero for final speed, and Equation-1 into the formula.
Here d' is the stopping distance that we want to look for.
We crossed out 2 in above and below.
We multiply both sides by d.
We crossed out v^2 on both sides.
Hence, by using two significant figures, the stopping distance if the car is initially traveling at speed 7.0v is 49d.
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Keywords: a car traveling at speed v, takes distance d to stop after the brakes are applied, the stopping distance, if the car is initially traveling at speed 7.0v, the acceleration due to the braking is the same, two significant figures.
Answer:
Part A - 3N/m
Part B - see attachment
Part C - 4.9 × 10-³J
Part D - E = 1/2kd² + 1/2mv² + mgh
Explanation:
This problem requires the knowledge of simple harmonic motion for cimplete solution. To find the spring constant in part A the expression relating the force applied to a spring and the resulting stretching of the spring (hooke's law) is required which is F = kx.
The free body diagram can be found in the attachment. Fp(force of pull), Ft(Force of tension) and W(weight).
The energy stored in the pring as a result of the stretching of d = 5.7cm is 1/2kd².
Part D
Three forces act on the spring-monkey system and they do work in different forms: kinetic energy 1/2mv² , elastic potential
energy due to the restoring force in the spring or the tension force 1/2kd², and the gravitational potential energy mgh of the position of the system. So the total energy of the system E = 1/2kd² + 1/2mv² + mgh.
