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Arlecino [84]
2 years ago
8

A company sells apples in packages of 444. The masses of the individual apples are normally distributed with a mean of 175\,\tex

t{g}175g175, start text, g, end text and a standard deviation of 15\,\text{g}15g15, start text, g, end text. Assume that the weights of apples are independent from each other.
Mathematics
1 answer:
erastova [34]2 years ago
5 0

Answer: let the probability of  weights less than 160 be the required value, then, using z-score formula

z-score =( x - ∪) ÷ Ф where, x is 160, ∪ is population mean = 175,

Ф is the population standard deviation = 15

  z-score = (160 - 175) ÷ 15 = -1

p(z< -1) = 0.159

Step-by-step explanation:

the question is not complete. Assuming that the missing figure is 160 representing the required weights ess than the normal weights of 175.

step 1. obtain the z-score value by using the formula

          z =( x - ∪) ÷ Ф

step 2. obtain the probability of weights less than 160 from normal distribution table. since z-score value is -1,the probability is obtained as 0.159 that is 15.9%

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

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Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

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